anonymous
  • anonymous
Using the completing-the-square method, rewrite f(x) = x2 + 4x − 1 in vertex form. f(x) = (x + 2)2 + 1 f(x) = (x + 2)2 f(x) = (x + 2)2 + 4 f(x) = (x + 2)2 − 5
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
welcome to open study
anonymous
  • anonymous
tanks
anonymous
  • anonymous
yeah

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More answers

anonymous
  • anonymous
can you help me with this problem
anonymous
  • anonymous
what does it mean by "rewrite f(x) = x2 + 4x − 1 in vertex form."
anonymous
  • anonymous
@Mehek14
anonymous
  • anonymous
@marigirl @moazzam07
marigirl
  • marigirl
factorizing, so basically when you expand it out again, you should have your original equation.
anonymous
  • anonymous
but how do i turn fx to vetex form
anonymous
  • anonymous
vertex
anonymous
  • anonymous
o i didnt see where you said factor sorry
marigirl
  • marigirl
vertex form also means turning point on graph. i.e at which point on the x axis will the parabola have its minimum point. Best way to go about is start factorizing the equation given to you f(x) = x^2 + 4x − 1 May start factorising first part - x^2+4x .. what will that get us to
anonymous
  • anonymous
x(x+4) ???
marigirl
  • marigirl
let try it another way .. i am going to factorise it to \[f(x)= (x+2)^{2}\] This will ensure I have it in vertex form... now i need to manipulate it a little so that my final equation will look like \[f(x)=x ^{2}+4x-1\] so now, what constant value will i need to add to the top equation to make it same as the second equation ..
anonymous
  • anonymous
i dont know 2?
marigirl
  • marigirl
see what u get when you expand f(x)=(x+2^2: we get x^2+4x+4 ..... but i need x^2+4x-1 .. so what number do i need to add/minus so i wil get to x^2+4x-
anonymous
  • anonymous
1
marigirl
  • marigirl
i need to minus 5
anonymous
  • anonymous
where u get that from lol im so confused
marigirl
  • marigirl
(x+2)^2-5
marigirl
  • marigirl
sorry i dont think i helped...
anonymous
  • anonymous
oooo ok i understand wher i am i was confused with the vertex form i mixed it with a different formula
anonymous
  • anonymous
no actually you did i just thought to hard
marigirl
  • marigirl
ok, well you can always expand the answers given to you and see which is the original equation
anonymous
  • anonymous
ok thanksss

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