Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B? 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

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Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B? 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

Mathematics
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@stacy.reed08
ok, what there a picture or anything with this? I'm assuming line segment is a diagonal.
*was, not what :)

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Nope there was no picture along with this
ok, give me a minute to think on this. I'm a little rusty.
ok, pretty sure you can use the distance formula...
Yeah i was thinking the same, but i'm an absolute slug when it comes to math
|dw:1440105746620:dw|
Omg that makes it so much more clear
plug in what you know...you know (x1, y1) and you know the distance.
So its the first option
that's what it looks like to me :)
d= (x-6)^2+ (y-5)^2
You're a god
Have any more time to spare lol
well the square root of all of that (what you typed above)
Yes lol
how many more problems do you have?

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