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anonymous
 one year ago
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B?
5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared
5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared
5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared
5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared
anonymous
 one year ago
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B? 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, what there a picture or anything with this? I'm assuming line segment is a diagonal.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope there was no picture along with this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, give me a minute to think on this. I'm a little rusty.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, pretty sure you can use the distance formula...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah i was thinking the same, but i'm an absolute slug when it comes to math

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440105746620:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Omg that makes it so much more clear

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plug in what you know...you know (x1, y1) and you know the distance.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So its the first option

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what it looks like to me :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have any more time to spare lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well the square root of all of that (what you typed above)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how many more problems do you have?
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