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anonymous

  • one year ago

Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B? 5 = square root of the quantity of x minus 6 all squared plus y minus 5 all squared 5 = square root of the quantity of x minus 5 all squared plus y minus 6 all squared 5 = square root of the quantity of x plus 6 all squared plus y plus 5 all squared 5 = square root of the quantity of x plus 5 all squared plus y plus 6 all squared

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  1. anonymous
    • one year ago
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    @stacy.reed08

  2. anonymous
    • one year ago
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    ok, what there a picture or anything with this? I'm assuming line segment is a diagonal.

  3. anonymous
    • one year ago
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    *was, not what :)

  4. anonymous
    • one year ago
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    Nope there was no picture along with this

  5. anonymous
    • one year ago
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    ok, give me a minute to think on this. I'm a little rusty.

  6. anonymous
    • one year ago
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    ok, pretty sure you can use the distance formula...

  7. anonymous
    • one year ago
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    Yeah i was thinking the same, but i'm an absolute slug when it comes to math

  8. anonymous
    • one year ago
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    |dw:1440105746620:dw|

  9. anonymous
    • one year ago
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    Omg that makes it so much more clear

  10. anonymous
    • one year ago
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    plug in what you know...you know (x1, y1) and you know the distance.

  11. anonymous
    • one year ago
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    So its the first option

  12. anonymous
    • one year ago
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    that's what it looks like to me :)

  13. anonymous
    • one year ago
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    d= (x-6)^2+ (y-5)^2

  14. anonymous
    • one year ago
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    You're a god

  15. anonymous
    • one year ago
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    Have any more time to spare lol

  16. anonymous
    • one year ago
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    well the square root of all of that (what you typed above)

  17. anonymous
    • one year ago
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    Yes lol

  18. anonymous
    • one year ago
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    how many more problems do you have?

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spraguer (Moderator)
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