Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3x + 3. y = 3 over 2x − 3 y = 3 over 2x + 3 y = negative 2 over 3x + 23 over 3 y = negative 2 over 3x − 23 over 3

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Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3x + 3. y = 3 over 2x − 3 y = 3 over 2x + 3 y = negative 2 over 3x + 23 over 3 y = negative 2 over 3x − 23 over 3

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@stacy.reed08
ok, I recommend using the slope-intercept equation. do you know what that one is?
y=mx+b?

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Other answers:

perfect, so they gave you an x and a y when they said it passed through (7,3) so start by plugging that in.
3=m(7)+b?
good, now if 2 lines are parallel, what does that mean for their slopes?
they're the same
so plug that in
y = negative 2 over 3x + 23 over 3?
keep what you had before...
|dw:1440106334373:dw|
What do you mean by plugging the fact that they have the same slopes then?
Oh ok so 3=-2/3(7)+b
great, now solve for b :)
How lol
ohhh b=23 over 3?
yup :) so now go back to y=mx+b
plug in the slope and the y-intercept and you have your equations.
so it would be the third option
yes. great work!
lol thanks i got some more
Yeah shes right
ok, I have about 2 more minutes.
lol so do i
10, not 2...seriously, my brain is fried.

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