Destinyyyy
  • Destinyyyy
Word problem.. The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 428 yards, what are its dimensions?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Destinyyyy
  • Destinyyyy
The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 428 yards, what are its dimensions?
xapproachesinfinity
  • xapproachesinfinity
|dw:1440108313131:dw|
xapproachesinfinity
  • xapproachesinfinity
length is 9 yards longer than the width we call it w so that would be w+9

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

xapproachesinfinity
  • xapproachesinfinity
we already know the perimeter to be 428 yards and we know tht Perimeter = the sum of all length and widths
xapproachesinfinity
  • xapproachesinfinity
so perimeter= 2w +2(w+9) then 428=2w+2(w+9)
xapproachesinfinity
  • xapproachesinfinity
solve for w to find width then for length just add 9 to what you found
xapproachesinfinity
  • xapproachesinfinity
those would be your dimesions
Destinyyyy
  • Destinyyyy
w= 102.5?
Destinyyyy
  • Destinyyyy
@xapproachesinfinity
anonymous
  • anonymous
im not smart enough
xapproachesinfinity
  • xapproachesinfinity
yes correct
xapproachesinfinity
  • xapproachesinfinity
that's width length is w+9
Destinyyyy
  • Destinyyyy
Okay. w= 102.5 l= 111.5
xapproachesinfinity
  • xapproachesinfinity
yes
Destinyyyy
  • Destinyyyy
It says its incorrect .
Vocaloid
  • Vocaloid
method is correct, equation is incorrect "the length is 9 yards longer than quadriple the width" means that l = 4w + 9 repeat the same steps as above, using this new equation
Vocaloid
  • Vocaloid
428 = 2w + 2(4w+9) solve for w, and then l, as before.
anonymous
  • anonymous
l=4w+9 2(l+w)=428
Destinyyyy
  • Destinyyyy
w=41 l=50
Destinyyyy
  • Destinyyyy
l= 50 is incorrect
anonymous
  • anonymous
l+w=428/2=214 4w+9+w=214 5w=214-9=205 w=205/5=41 l=4*41+9=164+9=173
Destinyyyy
  • Destinyyyy
Thank you.
anonymous
  • anonymous
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.