Word problem.. The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 428 yards, what are its dimensions?

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Word problem.. The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 428 yards, what are its dimensions?

Mathematics
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The length of a new rectangular playing field is 9 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 428 yards, what are its dimensions?
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length is 9 yards longer than the width we call it w so that would be w+9

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Other answers:

we already know the perimeter to be 428 yards and we know tht Perimeter = the sum of all length and widths
so perimeter= 2w +2(w+9) then 428=2w+2(w+9)
solve for w to find width then for length just add 9 to what you found
those would be your dimesions
w= 102.5?
im not smart enough
yes correct
that's width length is w+9
Okay. w= 102.5 l= 111.5
yes
It says its incorrect .
method is correct, equation is incorrect "the length is 9 yards longer than quadriple the width" means that l = 4w + 9 repeat the same steps as above, using this new equation
428 = 2w + 2(4w+9) solve for w, and then l, as before.
l=4w+9 2(l+w)=428
w=41 l=50
l= 50 is incorrect
l+w=428/2=214 4w+9+w=214 5w=214-9=205 w=205/5=41 l=4*41+9=164+9=173
Thank you.
yw

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