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anonymous

  • one year ago

@vocaloid @imqwerty

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  1. anonymous
    • one year ago
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    The picture below shows a box sliding down a ramp: A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 68 degrees. The length of AB is 14 feet. What is the distance, in feet, that the box has to travel to move from point A to point C? 14 sin 68° 14 cosec 68° 14 divided by sec 68 degrees 14 divided by cot 68 degrees

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    i saw your post @wel

  4. anonymous
    • one year ago
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    @welshfella

  5. welshfella
    • one year ago
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    sin 68 = 14 / AC

  6. anonymous
    • one year ago
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    so would it be the first option then?

  7. welshfella
    • one year ago
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    There might be a typo in your choices The correct answer is not there

  8. anonymous
    • one year ago
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    14 sin 68° 14 cosec 68° 14 divided by sec 68 degrees 14 divided by cot 68 degrees

  9. anonymous
    • one year ago
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    What is the distance, in feet, that the box has to travel to move from point A to point C?

  10. anonymous
    • one year ago
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    Are you sure? there isn't an answer there that is even remotely close to the real answer?

  11. welshfella
    • one year ago
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    sin 68 = 14 / AC cross multiply AC * sin 68 = 14 divide both sides by sin 68 AC = 14 / sin 68

  12. anonymous
    • one year ago
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    what about 14 / sec 68?

  13. welshfella
    • one year ago
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    maybe sec in option C should be sin

  14. anonymous
    • one year ago
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    yes maybe, anyways thanks for the help!

  15. welshfella
    • one year ago
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    yw

  16. anonymous
    • one year ago
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    can you answer another question for me?

  17. anonymous
    • one year ago
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    Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: ABC is a right triangle with measure of angle ABC equal to 90 degrees and length of AB equal to 400 feet. There is a point C on BD such that measure of angle ACB is 60 degrees and measure of angle ADC is 30 degrees. What is the distance, CD, between the boats?

  18. anonymous
    • one year ago
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  19. welshfella
    • one year ago
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    oh hold 1/sin = cosec so its B 14 cosec 68

  20. welshfella
    • one year ago
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    First question answer is B

  21. anonymous
    • one year ago
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    oh alrightt thanks

  22. anonymous
    • one year ago
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    But please help me on this question as well, i dont have alot of time and need to be done with two more questions including the one i just sent!

  23. welshfella
    • one year ago
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    Find length of BD from the big triangle ABD using tan 30 = 400 / BD then find length of BC from the small triangle using tan 60 = 400 / BC then CD = BD - BC

  24. anonymous
    • one year ago
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    when i do tan 30 i get .5

  25. anonymous
    • one year ago
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    and tan 60 is 1.7

  26. anonymous
    • one year ago
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    Would you mind just giving me the answer? I know it's the right thing to do, but i'll learn it soon enough I think and i have to go in like 10 minutes

  27. anonymous
    • one year ago
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    it's not the right thing to do**

  28. welshfella
    • one year ago
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    tan 30 = 0.5774 and tan 60 = 1.7321

  29. welshfella
    • one year ago
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    BC = 400 / 1.7321 and BD = 400 / 0.5774

  30. anonymous
    • one year ago
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    BC= 230.933

  31. welshfella
    • one year ago
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    work those 2 out then DC = BD - BC

  32. anonymous
    • one year ago
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    BD= 692.761

  33. welshfella
    • one year ago
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    right

  34. anonymous
    • one year ago
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    DC=461.828

  35. anonymous
    • one year ago
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    thank you so much!

  36. anonymous
    • one year ago
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    One final question please!!

  37. welshfella
    • one year ago
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    that right yw

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