@vocaloid @imqwerty

- anonymous

@vocaloid @imqwerty

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- anonymous

The picture below shows a box sliding down a ramp:
A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 68 degrees. The length of AB is 14 feet.
What is the distance, in feet, that the box has to travel to move from point A to point C?
14 sin 68°
14 cosec 68°
14 divided by sec 68 degrees
14 divided by cot 68 degrees

- anonymous

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- anonymous

i saw your post @wel

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## More answers

- anonymous

@welshfella

- welshfella

sin 68 = 14 / AC

- anonymous

so would it be the first option then?

- welshfella

There might be a typo in your choices
The correct answer is not there

- anonymous

14 sin 68°
14 cosec 68°
14 divided by sec 68 degrees
14 divided by cot 68 degrees

- anonymous

What is the distance, in feet, that the box has to travel to move from point A to point C?

- anonymous

Are you sure? there isn't an answer there that is even remotely close to the real answer?

- welshfella

sin 68 = 14 / AC
cross multiply
AC * sin 68 = 14
divide both sides by sin 68
AC = 14 / sin 68

- anonymous

what about 14 / sec 68?

- welshfella

maybe sec in option C should be sin

- anonymous

yes maybe, anyways thanks for the help!

- welshfella

yw

- anonymous

can you answer another question for me?

- anonymous

Two boats start their journey from the same point A and travel along directions AC and AD, as shown below:
ABC is a right triangle with measure of angle ABC equal to 90 degrees and length of AB equal to 400 feet. There is a point C on BD such that measure of angle ACB is 60 degrees and measure of angle ADC is 30 degrees.
What is the distance, CD, between the boats?

- anonymous

##### 1 Attachment

- welshfella

oh hold 1/sin = cosec
so its B 14 cosec 68

- welshfella

First question answer is B

- anonymous

oh alrightt thanks

- anonymous

But please help me on this question as well, i dont have alot of time and need to be done with two more questions including the one i just sent!

- welshfella

Find length of BD from the big triangle ABD
using tan 30 = 400 / BD
then find length of BC from the small triangle using
tan 60 = 400 / BC
then CD = BD - BC

- anonymous

when i do tan 30 i get .5

- anonymous

and tan 60 is 1.7

- anonymous

Would you mind just giving me the answer? I know it's the right thing to do, but i'll learn it soon enough I think and i have to go in like 10 minutes

- anonymous

it's not the right thing to do**

- welshfella

tan 30 = 0.5774
and tan 60 = 1.7321

- welshfella

BC = 400 / 1.7321
and BD = 400 / 0.5774

- anonymous

BC= 230.933

- welshfella

work those 2 out then DC = BD - BC

- anonymous

BD= 692.761

- welshfella

right

- anonymous

DC=461.828

- anonymous

thank you so much!

- anonymous

One final question please!!

- welshfella

that right
yw

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