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hey @welshfella please help!
probability of getting a white box for first winner = 6/24 for the second player there are now 5 white boxes and total of 23 boxes so what is probability of second player getting a white bos?
how do i get the answer.. what do i have to solve?
the important thing to remember for second draw is there are 5 white and total 23 - so what is Probabilty of picking a white box from this 23 boxes?
hwo do i do that? im confused
well for 6 and 24 the answer was 6/24 so for 5 and 23 it will be ?
cant you see the pattern here?
probability = number of white boxes / total number of boxes
number of white boxes = 5 , total number of boxes = 23
I cant put it plainer than that
just plug those numbers into the formula for the probability
yes but they want it as a fraction 5/23
now as the 2 events are independent you multiply the 2 probabilities require probability = 6/24 * 5/23
i got 5/92
k gimme a sec
while im finishing my own work try googling the question
yes but i dont know what the answer is still
i did and i got nothing
you are talking about the candy question right?
its number 2 6/24 times 5/23 the reason this is the answer is because on the first pick there are 4 colors and each color has 6 boxes each 6*4=24 however after the first white box is taken there are only 23 boxes left in total leaving only 5 white boxes left since one white box was removed from the booth.so the new chance of picking a white box would be 5/23.the chance of picking two white boxes in a row would be calculated by multiplying the chance of picking the white box the first time and the new chance of picking the white box the second time.so the chance of picking two white boxes in a row would be 30/552 without simplifying.from there I think you can do the rest.
i got 30/552
oh i was gonna say... no i didnt lol
ok i have more questions.. please help :)