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- anonymous

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- schrodinger

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- anonymous

29,30,31

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- Vocaloid

well, it says that point S is between R and T so
RT = RS + ST

- Vocaloid

60 = 3x - 16 + 4x - 8
the first step is to solve for x, do you think you can take it from here?

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- anonymous

hold i'll do it then see if im correct

- anonymous

x=12?

- Vocaloid

yup, that's the first step.
now that we know what x is, we can now find RS and ST
RS = 3x - 16 = ?
ST = 4x - 8 = ?

- anonymous

doin it hold on

- anonymous

rs is 24

- anonymous

st is 40

- Vocaloid

check rs again. st is right

- Vocaloid

3(12)-16 = ?

- anonymous

lol sorry 20

- Vocaloid

yeah.

- Vocaloid

problem #30 is basically the same thing, do you wanna give it a shot?

- anonymous

k

- anonymous

i got 7

- anonymous

x=7

- anonymous

rs i got 6

- anonymous

st i got 11

- anonymous

@vocaloid when you get a chance

- Vocaloid

yup those are all correct, ready to move to #31?

- anonymous

yup :)

- anonymous

@vocaloid

- anonymous

i have no idea how to do it

- Vocaloid

ah, sorry, got distracted there for a sec
let's draw the diagram and label it based on what the problem tells us
|dw:1440113699458:dw|

- anonymous

okY

- Vocaloid

AD = 12, so let's mark that right away|dw:1440113728465:dw|

- Vocaloid

now the problem tells us that AC and CD are equal, so what do you think each of them are?|dw:1440113761200:dw|

- anonymous

6?

- Vocaloid

righto! let's put that on our diagram|dw:1440113809996:dw|

- Vocaloid

now, the problem also tells us that AB and BC are equal, so what do you think they are?
|dw:1440113840316:dw|

- anonymous

3?

- Vocaloid

yup, now that we have enough info to keep going

- Vocaloid

now, it wants us to find the length of every segment in the diagram, so I'll make a list here:
AB = 3
BC = 3
CD = 6
AC = 6
CD = 6
BD = 9
AD = 12
so, how many are greater than 3?

- anonymous

5

- Vocaloid

so our probability is 5/7

- Vocaloid

(since there are 7 total segments)
and that ends up being our final answer for #31

- anonymous

why are there multiple CD's

- Vocaloid

oh crap I guess I must have counted it twice, haha...
I guess our probability should be 4/6 then

- Vocaloid

or 2/3

- anonymous

CAn you help with one more then im done i think this one is easy idk

- Vocaloid

sure

- anonymous

ill be posting the image now too

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- anonymous

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- anonymous

press and hold ctrl and scroll to make it bigger if you need too

- Vocaloid

well, the abdomen is easy enough, it's 2 and 1/4 of an inch, just reading off the ruler

- Vocaloid

for the thorax, the right end is at the 4-inch mark, approximately, and the left end is at 2 1/4 inches
so (4) - (2 and 1/4) = 1 and 3/4 inch for the thorax

- anonymous

huh?

- Vocaloid

hm? where did you get lost?

- anonymous

so (4) - (2 and 1/4) = 1 and 3/4 inch for the thorax

- Vocaloid

well, we can measure the abdomen by looking at the ruler, since the abdomen starts at 0
for the thorax, though, it doesn't start at 0 so we need to find both ends and subtract

- anonymous

ooooh okay i get it so 1 and 3/4 for thorax

- anonymous

so its 1/2 inch bigger

- anonymous

9/4-7/4

- Vocaloid

right.

- Vocaloid

that's it

- anonymous

okay thanks that's it for the night/day wherever you live :)

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