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anonymous
 one year ago
CHECK MY ANSWER?
Determine if the graph is symmetric about the xaxis, the yaxis, or the origin.
r = 5  5 cos θ
I got yaxis.
anonymous
 one year ago
CHECK MY ANSWER? Determine if the graph is symmetric about the xaxis, the yaxis, or the origin. r = 5  5 cos θ I got yaxis.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u have a graph to attach

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 @ganeshie8 @mathstudent55 anybody? please check my answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is no graph with the problem. i plugged it into wolfram alpha

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I don't really like how wolfram alpha sets up their graphs and how there's no customization The online grapher "fooplot" is a better choice for polar plots http://fooplot.com/plot/dreqosz0s8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well that looks completely different from the wolfram alpha one!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From wolfram I got that the graph was symmetric along the y axis and with this one im getting its symmetric along the x axis..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what did you type into wolfram alpha?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I see. It's thinking you want to graph y = 55*cos(x) on the regular cartesian xy coordinate system (not the polar coordinate system)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you type in "5  5 cos θ polar", that key term "polar" at the end, you get a polar graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, alright, I see...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1fooplot is still a better choice though because you can move the graph around, zoom in/out, etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it seems my graph will be symmetrical along the x axis after all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you very much for your help : )

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome
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