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anonymous

  • one year ago

WILL GIVE MEDAL!!! Explain how to find instantaneous velocity and find it for s(t) = -3 + 4t^2 when t = 5 seconds. @Mertsj @zepdrix @Hero @mathstudent55

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  1. anonymous
    • one year ago
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    http://www.wikihow.com/Calculate-Instantaneous-Velocity Go to website above to find out how to find instantaneous velocity

  2. anonymous
    • one year ago
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    @raesal

  3. Hero
    • one year ago
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    @raesal Just evaluate s(5).

  4. anonymous
    • one year ago
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    So -3+4(5)^2=97. The instantaneous velocity would be 97? @Hero

  5. Hero
    • one year ago
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    Actually, you should find v(t) first, then evaluate v(5).

  6. anonymous
    • one year ago
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    How do I find v(t)? @Hero

  7. Hero
    • one year ago
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    v(t) = s'(t)

  8. anonymous
    • one year ago
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    so v(t)= -3 + 4t^2?

  9. Hero
    • one year ago
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    You have to calculate s'(t) first. In other words, take the derivative of s(t) to get v(t).

  10. anonymous
    • one year ago
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    The derivative of -3 + 4t^2 is 8t. so 8t=vt? Then what?

  11. Hero
    • one year ago
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    Now evaluate v(5).

  12. anonymous
    • one year ago
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    so 8*5=40. so the instantaneous velocity is 40?

  13. anonymous
    • one year ago
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    But I have the correct number, 40, correct? @Hero

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spraguer (Moderator)
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