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anonymous

  • one year ago

The function f(x)= cot(3x-pi/2) has ___.? A. period pi/3 and asymptote at x=pi/6 B. period 2pi/3 and asymptote at x=pi/6 C. period 2pi/3 and asymptote at x=0 D. period pi/3 and asymptote at x=0

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  1. jim_thompson5910
    • one year ago
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    the period of the general cotangent function shown below is T = pi/B y = A*cot(Bx - C) + D

  2. jim_thompson5910
    • one year ago
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    let me know if that's enough to get you started

  3. anonymous
    • one year ago
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    I still don't quiet understand

  4. jim_thompson5910
    • one year ago
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    do you see how the Bx and 3x match up?

  5. anonymous
    • one year ago
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    yeah

  6. jim_thompson5910
    • one year ago
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    so B = 3 and you plug that into T = pi/B to get pi/3 as the period

  7. anonymous
    • one year ago
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    oh okay. And then how would I find the asymptote ?

  8. jim_thompson5910
    • one year ago
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    what happens when you plug in x = 0 ?

  9. anonymous
    • one year ago
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    you get 0?

  10. jim_thompson5910
    • one year ago
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    yes, so because x = 0 produces a single number as an output, this means x = 0 is NOT a vertical asymptote

  11. jim_thompson5910
    • one year ago
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    that leaves x = pi/6 to be an asymptote sure enough if you plug in x = pi/6, you should get NAN or UND or whatever error your calculator will spit out

  12. anonymous
    • one year ago
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    so it's not D?

  13. jim_thompson5910
    • one year ago
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    it's A actually

  14. jim_thompson5910
    • one year ago
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    yeah D is out because f(0) is defined

  15. anonymous
    • one year ago
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    Okay i understand thank you so much:)

  16. jim_thompson5910
    • one year ago
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    glad to be of help

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