anonymous
  • anonymous
The function f(x)= cot(3x-pi/2) has ___.? A. period pi/3 and asymptote at x=pi/6 B. period 2pi/3 and asymptote at x=pi/6 C. period 2pi/3 and asymptote at x=0 D. period pi/3 and asymptote at x=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
the period of the general cotangent function shown below is T = pi/B y = A*cot(Bx - C) + D
jim_thompson5910
  • jim_thompson5910
let me know if that's enough to get you started
anonymous
  • anonymous
I still don't quiet understand

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jim_thompson5910
  • jim_thompson5910
do you see how the Bx and 3x match up?
anonymous
  • anonymous
yeah
jim_thompson5910
  • jim_thompson5910
so B = 3 and you plug that into T = pi/B to get pi/3 as the period
anonymous
  • anonymous
oh okay. And then how would I find the asymptote ?
jim_thompson5910
  • jim_thompson5910
what happens when you plug in x = 0 ?
anonymous
  • anonymous
you get 0?
jim_thompson5910
  • jim_thompson5910
yes, so because x = 0 produces a single number as an output, this means x = 0 is NOT a vertical asymptote
jim_thompson5910
  • jim_thompson5910
that leaves x = pi/6 to be an asymptote sure enough if you plug in x = pi/6, you should get NAN or UND or whatever error your calculator will spit out
anonymous
  • anonymous
so it's not D?
jim_thompson5910
  • jim_thompson5910
it's A actually
jim_thompson5910
  • jim_thompson5910
yeah D is out because f(0) is defined
anonymous
  • anonymous
Okay i understand thank you so much:)
jim_thompson5910
  • jim_thompson5910
glad to be of help

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