anonymous
  • anonymous
Find the standard form of the equation of the parabola with a focus at (-4, 0) and a directrix at x = 4.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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misty1212
  • misty1212
|dw:1440121717847:dw|
misty1212
  • misty1212
HJI!!
misty1212
  • misty1212
you need the vertex first, also which way it is oriented then it is quite quick do you know the vertex?

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More answers

anonymous
  • anonymous
0,0?
misty1212
  • misty1212
yes !
misty1212
  • misty1212
and how is it oriented? |dw:1440121829542:dw|
anonymous
  • anonymous
first?
misty1212
  • misty1212
yes again
misty1212
  • misty1212
|dw:1440121936412:dw|
misty1212
  • misty1212
because it opens to the left, that means the \(y\) term is squared, and it will look like \[y^2=px\]
misty1212
  • misty1212
all you need is \(p\) the distance from the vertex to the focus, or from the directrix to the vertex what is that distance?
misty1212
  • misty1212
oops i made a typo \[y^2=4px\] is what i meant
anonymous
  • anonymous
p=4
misty1212
  • misty1212
ok so final answer \[y^2=-16x\]
misty1212
  • misty1212
minus because it opens to the left
anonymous
  • anonymous
oh okay so you just have to look for each part and then put it together THANK YOU SO MUCH!!
misty1212
  • misty1212
right want to check the answer?
misty1212
  • misty1212
\[\color\magenta\heartsuit\] http://www.wolframalpha.com/input/?i=parabola+y%5E2%3D-16x
anonymous
  • anonymous
y = negative one divided by sixteenx2
misty1212
  • misty1212
oh no!
misty1212
  • misty1212
the y term is squared, not the x term
anonymous
  • anonymous
ohh yeah sorry haha
misty1212
  • misty1212
if \[y^2=-16x\] is not an "answer choice" try \[x=-\frac{1}{16}y^2\]
anonymous
  • anonymous
could we do another one like this and you help me the same way?
misty1212
  • misty1212
kk
anonymous
  • anonymous
Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.
misty1212
  • misty1212
|dw:1440122328669:dw|
misty1212
  • misty1212
vertex?
anonymous
  • anonymous
so it open down? vertex is 0,0
misty1212
  • misty1212
yeah opens down so the x term is squared and its coefficient it negative
misty1212
  • misty1212
distance is clear right?
anonymous
  • anonymous
p=9
misty1212
  • misty1212
right so \[x^2=-36y\] should do it
anonymous
  • anonymous
wait how did 36 come from 9
misty1212
  • misty1212
\[4\times 9\]
misty1212
  • misty1212
\[x^2=4py\]
anonymous
  • anonymous
ohhh yeah okay haah and wouldn't it be y=-1/36x2
misty1212
  • misty1212
that too
anonymous
  • anonymous
oh okay
anonymous
  • anonymous
thank you so much! If I have any more tonight ill tag you in them :)
misty1212
  • misty1212
\[\huge\color\magenta\heartsuit\]

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