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HI!!

ready?

yes

first the \(-2\) outside means a) flip everything, then
b) square it

Okay

so first
\[\huge\frac{1}{\left(-3u^2v^3\right)^2}\]

Okay but where did the 2 come from in the parenthesis

\[\huge\frac{1}{\left(-3u^3v^3\right)^2}=\frac{1}{9u^6v^6}\]

oh oops that was a typo

Oh okay :) i'm following

should have been \[\huge\frac{1}{\left(-3u^3v^3\right)^2}\]

then square all
answer above is right though, looks like your choice A

ok sure \[\color\magenta\heartsuit\]

So i would flip it first right

no not here

the reason we flipped before was because there was a \(-2\) outside the parentheses

Oh okay so then i wouldn't flip it i would leave it the same

only one choice as \(x^9\) in it so we dont really need to do the rest

so i take the two common ones and add them

yeah you want to do it all?

Yes please cause i have a lot more questions like this and i want to make sure i understand them

ok lets take it slow

first off, unlike the last one there is no parentheses anywheres, so it is somewhat easier

you have a minus sign out front
that stays there

Okay

Alright

yes more or less

if the exponent is negative
a) if it is up bring it down
b) if it is down bring it up

if both terms have positive exponents, subtract the smaller one from the bigger one

here is an example
\[\frac{x^7}{x^{-3}}=x^{10}\] wheras
\[\frac{x^4}{x^{10}}=\frac{1}{x^6}\]

Okay that makes a little more since now

whew

Thanks