tootsi123
  • tootsi123
Please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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tootsi123
  • tootsi123
tootsi123
  • tootsi123
@jim_thompson5910
misty1212
  • misty1212
HI!!

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misty1212
  • misty1212
ready?
tootsi123
  • tootsi123
yes
misty1212
  • misty1212
first the \(-2\) outside means a) flip everything, then b) square it
tootsi123
  • tootsi123
Okay
misty1212
  • misty1212
so first \[\huge\frac{1}{\left(-3u^2v^3\right)^2}\]
misty1212
  • misty1212
then we need so square everything that means square \(-3\) to get \(9\) and also double each exponent
tootsi123
  • tootsi123
Okay but where did the 2 come from in the parenthesis
misty1212
  • misty1212
\[\huge\frac{1}{\left(-3u^3v^3\right)^2}=\frac{1}{9u^6v^6}\]
misty1212
  • misty1212
oh oops that was a typo
tootsi123
  • tootsi123
Oh okay :) i'm following
misty1212
  • misty1212
should have been \[\huge\frac{1}{\left(-3u^3v^3\right)^2}\]
misty1212
  • misty1212
then square all answer above is right though, looks like your choice A
tootsi123
  • tootsi123
thank you :) okay there is another question like it... can i post it and tell you how i would do it and then you tell me if i am doing it right or not??
misty1212
  • misty1212
ok sure \[\color\magenta\heartsuit\]
tootsi123
  • tootsi123
So i would flip it first right
misty1212
  • misty1212
no not here
misty1212
  • misty1212
the reason we flipped before was because there was a \(-2\) outside the parentheses
tootsi123
  • tootsi123
Oh okay so then i wouldn't flip it i would leave it the same
misty1212
  • misty1212
there is only one choice here that makes sense take a look you have \[\huge\frac{x^4}{x^{-5}}\] right?
misty1212
  • misty1212
the \(-5\) in the deominator means bring it up to the numerator as \(+5\) so \[\frac{x^4}{x^{-5}}=x^4\times x^5=x^{4+5}=x^9\]
misty1212
  • misty1212
only one choice as \(x^9\) in it so we dont really need to do the rest
tootsi123
  • tootsi123
so i take the two common ones and add them
misty1212
  • misty1212
yeah you want to do it all?
tootsi123
  • tootsi123
Yes please cause i have a lot more questions like this and i want to make sure i understand them
misty1212
  • misty1212
ok lets take it slow
misty1212
  • misty1212
first off, unlike the last one there is no parentheses anywheres, so it is somewhat easier
misty1212
  • misty1212
you have a minus sign out front that stays there
misty1212
  • misty1212
you also have \[\frac{2}{4}\] which is the same as \(\frac{1}{2}\) so there will be a 2 in the denominator
tootsi123
  • tootsi123
Okay
misty1212
  • misty1212
as for the x terms, you have \[\frac{x^4}{x^{-5}}\] the \(-5\) has a minus sign, so that comes upstairs as \(x^5\) which is why you get \[\frac{x^4}{x^{-5}}=x^4\times x^5=x^9\]
tootsi123
  • tootsi123
Alright
misty1212
  • misty1212
and for \[\frac{y^2}{y^5}\] the 5 is bigger than the 2, so subtract 2 from 5 in the denominator \[\frac{y^2}{y^5}=\frac{1}{y^{5-2}}=\frac{1}{y^3}\]
misty1212
  • misty1212
so in total, a) there is a - sign out front b) there is a 2 in the denominator c) there is a \(x^9\) in the numerator and d) a \(y^3\) in the denominator
tootsi123
  • tootsi123
Okay so which ever number is bigger you use that to decide whether or not you add or subtract and whether or not it says on the top or the bottom, am i right?
misty1212
  • misty1212
yes more or less
misty1212
  • misty1212
if the exponent is negative a) if it is up bring it down b) if it is down bring it up
misty1212
  • misty1212
if both terms have positive exponents, subtract the smaller one from the bigger one
misty1212
  • misty1212
here is an example \[\frac{x^7}{x^{-3}}=x^{10}\] wheras \[\frac{x^4}{x^{10}}=\frac{1}{x^6}\]
tootsi123
  • tootsi123
Okay that makes a little more since now
misty1212
  • misty1212
whew
tootsi123
  • tootsi123
Thanks

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