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tootsi123

  • one year ago

Please help

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  1. tootsi123
    • one year ago
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  2. tootsi123
    • one year ago
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    @jim_thompson5910

  3. misty1212
    • one year ago
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    HI!!

  4. misty1212
    • one year ago
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    ready?

  5. tootsi123
    • one year ago
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    yes

  6. misty1212
    • one year ago
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    first the \(-2\) outside means a) flip everything, then b) square it

  7. tootsi123
    • one year ago
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    Okay

  8. misty1212
    • one year ago
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    so first \[\huge\frac{1}{\left(-3u^2v^3\right)^2}\]

  9. misty1212
    • one year ago
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    then we need so square everything that means square \(-3\) to get \(9\) and also double each exponent

  10. tootsi123
    • one year ago
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    Okay but where did the 2 come from in the parenthesis

  11. misty1212
    • one year ago
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    \[\huge\frac{1}{\left(-3u^3v^3\right)^2}=\frac{1}{9u^6v^6}\]

  12. misty1212
    • one year ago
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    oh oops that was a typo

  13. tootsi123
    • one year ago
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    Oh okay :) i'm following

  14. misty1212
    • one year ago
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    should have been \[\huge\frac{1}{\left(-3u^3v^3\right)^2}\]

  15. misty1212
    • one year ago
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    then square all answer above is right though, looks like your choice A

  16. tootsi123
    • one year ago
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    thank you :) okay there is another question like it... can i post it and tell you how i would do it and then you tell me if i am doing it right or not??

  17. misty1212
    • one year ago
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    ok sure \[\color\magenta\heartsuit\]

  18. tootsi123
    • one year ago
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    So i would flip it first right

  19. misty1212
    • one year ago
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    no not here

  20. misty1212
    • one year ago
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    the reason we flipped before was because there was a \(-2\) outside the parentheses

  21. tootsi123
    • one year ago
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    Oh okay so then i wouldn't flip it i would leave it the same

  22. misty1212
    • one year ago
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    there is only one choice here that makes sense take a look you have \[\huge\frac{x^4}{x^{-5}}\] right?

  23. misty1212
    • one year ago
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    the \(-5\) in the deominator means bring it up to the numerator as \(+5\) so \[\frac{x^4}{x^{-5}}=x^4\times x^5=x^{4+5}=x^9\]

  24. misty1212
    • one year ago
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    only one choice as \(x^9\) in it so we dont really need to do the rest

  25. tootsi123
    • one year ago
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    so i take the two common ones and add them

  26. misty1212
    • one year ago
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    yeah you want to do it all?

  27. tootsi123
    • one year ago
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    Yes please cause i have a lot more questions like this and i want to make sure i understand them

  28. misty1212
    • one year ago
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    ok lets take it slow

  29. misty1212
    • one year ago
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    first off, unlike the last one there is no parentheses anywheres, so it is somewhat easier

  30. misty1212
    • one year ago
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    you have a minus sign out front that stays there

  31. misty1212
    • one year ago
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    you also have \[\frac{2}{4}\] which is the same as \(\frac{1}{2}\) so there will be a 2 in the denominator

  32. tootsi123
    • one year ago
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    Okay

  33. misty1212
    • one year ago
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    as for the x terms, you have \[\frac{x^4}{x^{-5}}\] the \(-5\) has a minus sign, so that comes upstairs as \(x^5\) which is why you get \[\frac{x^4}{x^{-5}}=x^4\times x^5=x^9\]

  34. tootsi123
    • one year ago
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    Alright

  35. misty1212
    • one year ago
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    and for \[\frac{y^2}{y^5}\] the 5 is bigger than the 2, so subtract 2 from 5 in the denominator \[\frac{y^2}{y^5}=\frac{1}{y^{5-2}}=\frac{1}{y^3}\]

  36. misty1212
    • one year ago
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    so in total, a) there is a - sign out front b) there is a 2 in the denominator c) there is a \(x^9\) in the numerator and d) a \(y^3\) in the denominator

  37. tootsi123
    • one year ago
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    Okay so which ever number is bigger you use that to decide whether or not you add or subtract and whether or not it says on the top or the bottom, am i right?

  38. misty1212
    • one year ago
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    yes more or less

  39. misty1212
    • one year ago
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    if the exponent is negative a) if it is up bring it down b) if it is down bring it up

  40. misty1212
    • one year ago
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    if both terms have positive exponents, subtract the smaller one from the bigger one

  41. misty1212
    • one year ago
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    here is an example \[\frac{x^7}{x^{-3}}=x^{10}\] wheras \[\frac{x^4}{x^{10}}=\frac{1}{x^6}\]

  42. tootsi123
    • one year ago
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    Okay that makes a little more since now

  43. misty1212
    • one year ago
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    whew

  44. tootsi123
    • one year ago
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    Thanks

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