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anonymous

  • one year ago

Let f(x) = sin-1x. Then, the domain of f(x) is [-1,1] and the range is all real numbers. True or False

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  1. anonymous
    • one year ago
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    Is it false?

  2. mathstudent55
    • one year ago
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    The range of sin x is [-1, 1] That means the domain of \(\sin ^{-1} x \) is [-1, 1]. The domain is correct.

  3. anonymous
    • one year ago
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    so True?

  4. mathstudent55
    • one year ago
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    The domain is correct, but the range is not. The range of the inverse sine function is limited to \([ -\dfrac{\pi}{2}, \dfrac{\pi}{2} ]\) The range is incorrect, so the answer must be false.

  5. anonymous
    • one year ago
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    Thanks:)

  6. mathstudent55
    • one year ago
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    You're welcome.

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