anonymous
  • anonymous
Let f(x) = sin-1x. Then, the domain of f(x) is [-1,1] and the range is all real numbers. True or False
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Is it false?
mathstudent55
  • mathstudent55
The range of sin x is [-1, 1] That means the domain of \(\sin ^{-1} x \) is [-1, 1]. The domain is correct.
anonymous
  • anonymous
so True?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathstudent55
  • mathstudent55
The domain is correct, but the range is not. The range of the inverse sine function is limited to \([ -\dfrac{\pi}{2}, \dfrac{\pi}{2} ]\) The range is incorrect, so the answer must be false.
anonymous
  • anonymous
Thanks:)
mathstudent55
  • mathstudent55
You're welcome.

Looking for something else?

Not the answer you are looking for? Search for more explanations.