## anonymous one year ago If sine of x equals 1 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

1. anonymous

$sinx = \frac{ 1 }{ 2 }$ as such correct?

2. anonymous

@iambatman yes

3. anonymous

Notice the ratio for sinx is $\sin(x) = \frac{ \text{opposite} }{ \text{hypotenuse} }$ so we can make a right triangle |dw:1440123129207:dw| we can use pythagorean theorem to find the adjacent side, can you do that please?

4. anonymous

|dw:1440123246771:dw|

5. anonymous

@iambatman

6. anonymous

$a^2+b^2 = c^2 \implies 1^2+b^2=2^2$$b^2 = 2^2 - 1^2 \implies b = \sqrt{4-1} = \sqrt{3}$ yup perfect!

7. anonymous

Now since we have adjacent side we should be able to find tanx and cosx now :)$cosx = \frac{ \text{adjacent} }{ \text{hypotenuse} }$ $tanx = \frac{ \text{opposite} }{ \text{adjcanet} }$

8. anonymous

So far so good?

9. anonymous

10. anonymous

Exactly! And tanx will be? :)

11. anonymous

12. anonymous

Perfect :) So we have $\cos(x) = \frac{ \sqrt{3} }{ 2 }$ and $\tan(x) = \frac{ 1 }{ \sqrt{3} }$ as you mentioned!

13. anonymous