If sine of x equals 1 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

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If sine of x equals 1 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

Mathematics
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\[sinx = \frac{ 1 }{ 2 }\] as such correct?
Notice the ratio for sinx is \[\sin(x) = \frac{ \text{opposite} }{ \text{hypotenuse} }\] so we can make a right triangle |dw:1440123129207:dw| we can use pythagorean theorem to find the adjacent side, can you do that please?

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|dw:1440123246771:dw|
\[a^2+b^2 = c^2 \implies 1^2+b^2=2^2\]\[b^2 = 2^2 - 1^2 \implies b = \sqrt{4-1} = \sqrt{3}\] yup perfect!
Now since we have adjacent side we should be able to find tanx and cosx now :)\[cosx = \frac{ \text{adjacent} }{ \text{hypotenuse} }\] \[tanx = \frac{ \text{opposite} }{ \text{adjcanet} }\]
So far so good?
yep! cos=rad3/2?
Exactly! And tanx will be? :)
and tan=1/rad3
Perfect :) So we have \[\cos(x) = \frac{ \sqrt{3} }{ 2 }\] and \[\tan(x) = \frac{ 1 }{ \sqrt{3} }\] as you mentioned!
so thats the whole answer
Yup, that's it! Nice work

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