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anonymous

  • one year ago

Solve the equation in the specified interval Secx=-3 -pi</x<pi

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    start with \[\cos(x)=-\frac{1}{3}\]

  3. misty1212
    • one year ago
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    then comes some difficulty

  4. anonymous
    • one year ago
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    Hey! Yes I started with that

  5. misty1212
    • one year ago
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    so now you are stuck since you don't know the answer to that

  6. anonymous
    • one year ago
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    Basically I'm stuck in this step

  7. misty1212
    • one year ago
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    you need to use a calculator to find \[\cos^{-1}(-\frac{1}{3})\]

  8. misty1212
    • one year ago
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    that will only give you one answer in quadrant 2 though

  9. anonymous
    • one year ago
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    Ok I got it

  10. misty1212
    • one year ago
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    |dw:1440123708272:dw|

  11. misty1212
    • one year ago
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    you want the other one, it is the negative of the first one

  12. misty1212
    • one year ago
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    |dw:1440123787810:dw|

  13. anonymous
    • one year ago
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    So first one is 1.91

  14. misty1212
    • one year ago
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    hmm let me check

  15. misty1212
    • one year ago
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    http://www.wolframalpha.com/input/?i=arccos%28-1%2F3%29 yeah looks good

  16. anonymous
    • one year ago
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    Ok so how do I get the opposite

  17. misty1212
    • one year ago
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    it is the negative of the first one

  18. anonymous
    • one year ago
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    -1.91?

  19. misty1212
    • one year ago
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    |dw:1440124243706:dw|

  20. misty1212
    • one year ago
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    scuse the bad picture yeah what you wrote

  21. anonymous
    • one year ago
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    Ok so how would you write to make it look like pi/2

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spraguer (Moderator)
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