anonymous
  • anonymous
Determine the standard form of the equation of the line that passes through (9, -4) and (6, 4) Haaaaalp
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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misty1212
  • misty1212
HI!!
anonymous
  • anonymous
Hi!
misty1212
  • misty1212
first we need the slope, because no matter what, if you want the equation of a line you need to have the slope do you know how to find ti?

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More answers

anonymous
  • anonymous
that would be -4+4 over 9+4 right?
misty1212
  • misty1212
not quite
misty1212
  • misty1212
you want to subtract, not add
anonymous
  • anonymous
Oh, okay. Hold on Lemme try.
misty1212
  • misty1212
kk
anonymous
  • anonymous
ok so its -8/5 ??
misty1212
  • misty1212
hmm \(9-6=?\)
anonymous
  • anonymous
oh dang! I was doing -4. My bad. So it's 4.
misty1212
  • misty1212
lets go slow
anonymous
  • anonymous
Yes
misty1212
  • misty1212
(9, -4) and (6, 4)
misty1212
  • misty1212
first we do it the think way, then we do it the math teacher way
anonymous
  • anonymous
Okay, it's like the third day of school. My brain doesn't work yet! sorry ahah.
misty1212
  • misty1212
from 6 to 9 in the x is right 3 units from 4 to -4 in the y is down 8 units right 3, down 8 slope is \[-\frac{8}{3}\]
anonymous
  • anonymous
okay, yes.
misty1212
  • misty1212
now the math teacher way \[\frac{y_2-y_1}{x_2-*x_1}=\frac{-4-4}{9-6}=-\frac{8}{3}\] or \[\frac{4-(-4)}{6-9}=\frac{8}{-3}=-\frac{8}{3}\] either way
anonymous
  • anonymous
okay, got it.
misty1212
  • misty1212
who goes to school in the middle of august?
misty1212
  • misty1212
ok no matter, now we have the the slope, and we can use the"point slope" formula because we have two points to choose form
anonymous
  • anonymous
Everyone where I'm from starts in August. I know some places in California start later. so y=mx+b?
anonymous
  • anonymous
wait, thats not right.
misty1212
  • misty1212
no that is the "slope intercept " form we are not there yet
anonymous
  • anonymous
y-y1 = m (x-x1)
misty1212
  • misty1212
yeah that one
anonymous
  • anonymous
Okay so -4 - 4 = -8/3 (9 - 6) ?
misty1212
  • misty1212
ooh no
misty1212
  • misty1212
the x and y in the formula are the variables you see in the answer only the \(x_1\) and \(y_1\) are numbers (as well as m )
misty1212
  • misty1212
you put numbers everywhere
anonymous
  • anonymous
oh. gosh ok. y+4= -8/3 (x-9)
misty1212
  • misty1212
looks a lot better now
anonymous
  • anonymous
subtracting a negative turns it into an addition basically, right?
misty1212
  • misty1212
right
misty1212
  • misty1212
now you should probably put it in "slope intercept" form aka solve for y
misty1212
  • misty1212
you know how to do that? takes the same two steps every time
anonymous
  • anonymous
Move the 4 to the other side?
misty1212
  • misty1212
no not yet
misty1212
  • misty1212
first distribute the \(-\frac{8}{3}\) on the left
anonymous
  • anonymous
oh yeah. so I multiply it or add it to the left?
misty1212
  • misty1212
multiply
misty1212
  • misty1212
\[y+4=-\frac{8}{3}+24\] if my arithmetic is correct
misty1212
  • misty1212
then don't "move the 4" subtract 4
misty1212
  • misty1212
sorry, typo there i meant \[y+4=-\frac{8}{3}x+24\] i dropped the x by mistake
anonymous
  • anonymous
wait, where did 24 come? distributing the slope on the right side?
misty1212
  • misty1212
yeah
misty1212
  • misty1212
cancel the 3's
misty1212
  • misty1212
\[-\frac{8}{3}\times (-9)=3\times 8=24\]
anonymous
  • anonymous
Okay, I understand.
misty1212
  • misty1212
so now we are at \[y+4=-\frac{8}{3}x+24\] subtract 4 from both sides and you are done
anonymous
  • anonymous
y=-8/3x+20
misty1212
  • misty1212
yup
misty1212
  • misty1212
took a while but i hope it is ok
anonymous
  • anonymous
Is that the final answer?
anonymous
  • anonymous
Thanks by the way (:
misty1212
  • misty1212
yeah it is the "final answer" as they say on tv you are quite welcome \[\color\magenta\heartsuit\]
anonymous
  • anonymous
haha, of course! I'll give you a medal.
misty1212
  • misty1212
thanks!

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