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@misty1212 , @jim_thompson5910
what equation did you get?
looks good to me
y = 85x + 55 is in the form y = mx+b m is your slope b is the y-intercept Since b = 55, this means you plot the point (0,55). Basically the point at 55 on the vertical y axis. This equation is a line, so you need 2 points. To get the next point, we use the slope 85 = 85/1 is the slope. The "85" up top means we move up 85 units, then we move 1 unit to the right to land on (1,140) So this graph is a straight line that goes through (0,55) and (1,140)
slope is 85, y intercept is 55
@jim_thompson5910 described how to graph it i think
it is not that easy because the scale will have to be different for the y and the x
I am so confused
you know how to graph a line in general?
plot the y intercept which is 55 |dw:1440126097602:dw|
@jim_thompson5910 is graphing it
plot the point (1,140) this point is found by going up 85 units, then to the right 1 unit |dw:1440126118938:dw|
after you get those two points, you draw a straight line through them
looks like you are being asked "how to graph it" i would start by saying put \((0,55)\) as the y intercept
there should really be nothing to the left of 0, because the situation only makes sense for positive values of x (they are numbers of days)
that is just something to plot you could plot \((0,55)\) and \((2,225)\) and \((5,480)\)
you can also think of it like this y = 85x + 55 y = 85*1 + 55 ... replace x with 1 y = 85 + 55 y = 140 that work shown above tells us that when x = 1, y = 140. So that's another way to get the ordered pair (1,140) as misty1212 points out, other ordered pairs like (2,225) and (5,480) lie on the graph too. you can move along the line using the slope or plug in the x values to get corresponding y values
try out x = 4 for instance. If you were to plug that into y = 85x + 55, what do you get for the value of y?