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Hi!
Have you tried solving it on your own first?

|dw:1440129172140:dw|

ok

Getting it?

Yeah, somewhat.

Could you please write what the second equation of motion is without substituting in the values?

\(\sf s=ut+\frac{1}{2}\times a \times t^2\)
s= distance
u=initial velocity
t= time
a=acceleration.

So the acceleration value is the force of gravity?

Ok, so \[V_{V} = \frac{ 9.75 + 1/2 * 9.8 * 16 }{ 4}\]
?

Yes.