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- freemap

The width of a rectangle is 8 cm less than its length. The perimeter of the rectangle is 52 cm.
What is the width of the rectangle?
A. 7 cm
B. 9 cm
C.15 cm
D. 17cm

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- freemap

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- freemap

- jim_thompson5910

`The width of a rectangle is 8 cm less than its length`
if the length is L, then what is the width in terms of L?

- freemap

W=L-8

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- jim_thompson5910

yes

- jim_thompson5910

now we use the perimeter of a rectangle formula
P = 2L + 2W

- jim_thompson5910

replace P with 52
replace W with L-8
doing this gives
52 = 2L + 2(L-8)
now solve for L

- freemap

Would you divide

- jim_thompson5910

yes but not right away

- freemap

l'm sorry but what would be L. Like the number I really don't understand

- jim_thompson5910

L stands for the length
it's unknown at this point, but when you solve for L, you figure out what the number for the length is

- jim_thompson5910

example: if 2L = 10, then L = 5

- freemap

52-2L =26

- jim_thompson5910

what would 2(L-8) turn into?

- freemap

2L -8

- freemap

2L - 16 i mean

- jim_thompson5910

so
52 = 2L + 2(L-8)
turns into
52 = 2L + 2L-16

- jim_thompson5910

then you combine the 2L terms
2L+2L = 4L
making 52 = 2L + 2L-16 turn into 52 = 4L-16

- freemap

Which now you divide by by 4 now?

- jim_thompson5910

not yet

- freemap

oh 16 + 52 is 68 and 68 divided by 4 is 17

- jim_thompson5910

yep, L = 17

- freemap

Thanks so much much could be check my other answer i'll post again so you ca get other medal

- jim_thompson5910

since L = 17, the width is W = L-8 = 17-8 = 9

- freemap

Thanks, i forgot about that part

- jim_thompson5910

they put that trap in

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