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anonymous

  • one year ago

I am timed! PLEASE Find an equation in standard form for the hyperbola with vertices at (0, ±8) and asymptotes at y equals inverse of plus minus 1 divided by 2x. y squared over 256 minus x squared over 64 equals 1 y squared over 64 minus x squared over 256 equals 1 y squared over 64 minus x squared over 16 equals 1 y squared over 64 minus x squared over 64 equals 1 Any ideas? Estimates? Guesses? Im under a time limit..

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  1. anonymous
    • one year ago
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    @nincompoop @ganeshie8 ?

  2. anonymous
    • one year ago
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    @jim_thompson5910 ?

  3. anonymous
    • one year ago
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    @jaredb2000 ?

  4. anonymous
    • one year ago
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    @iamawesome247 ?

  5. anonymous
    • one year ago
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    @whpalmer4 ?

  6. anonymous
    • one year ago
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    hi.

  7. anonymous
    • one year ago
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    [y2/64 - x2/b2\]

  8. anonymous
    • one year ago
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    and you need b2 to finish it

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    \[y =\frac{ 1}{ 2 } x\]

  11. anonymous
    • one year ago
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    asymptotes are y=±1/2 x.

  12. anonymous
    • one year ago
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    here. http://openstudy.com/study#/updates/536d2922e4b00a5ff135840a

  13. anonymous
    • one year ago
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    it willhelpu.

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spraguer (Moderator)
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