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anonymous
 one year ago
I am timed! PLEASE Find an equation in standard form for the hyperbola with vertices at (0, ±8) and asymptotes at y equals inverse of plus minus 1 divided by 2x.
y squared over 256 minus x squared over 64 equals 1
y squared over 64 minus x squared over 256 equals 1
y squared over 64 minus x squared over 16 equals 1
y squared over 64 minus x squared over 64 equals 1
Any ideas? Estimates? Guesses? Im under a time limit..
anonymous
 one year ago
I am timed! PLEASE Find an equation in standard form for the hyperbola with vertices at (0, ±8) and asymptotes at y equals inverse of plus minus 1 divided by 2x. y squared over 256 minus x squared over 64 equals 1 y squared over 64 minus x squared over 256 equals 1 y squared over 64 minus x squared over 16 equals 1 y squared over 64 minus x squared over 64 equals 1 Any ideas? Estimates? Guesses? Im under a time limit..

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop @ganeshie8 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and you need b2 to finish it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y =\frac{ 1}{ 2 } x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0asymptotes are y=±1/2 x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here. http://openstudy.com/study#/updates/536d2922e4b00a5ff135840a
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