@shalante can you help me with a problem

- anonymous

@shalante can you help me with a problem

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- anonymous

i just need help graphing something ..

- anonymous

Post it

- anonymous

okay so it says
Using the two functions listed below, insert numbers in place of letters a,b,c and d so that f(x) and g(x) inverses
\[f(x) = \frac{ x+a}{ b }\]

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## More answers

- anonymous

and g(x) - cx - d

- anonymous

for this part, i chose to do this f(x) = 2x + 5

- anonymous

to find g(x) we would have to find the inverse of f(x) right?

- anonymous

becaue i did it that way, and got this:
y=2x+5 (because i replaced f(x) and y)

- anonymous

am i correct so far?

- anonymous

f(x) has to be (x+any number)/a different number.

- anonymous

i got
x-5=2y/ 2

- anonymous

and then after simplifying that i got y = x-5 / 2

- anonymous

then where it says to evaluate g(x) i wasnt sure but this is how i did it:

- anonymous

is it g(x)-cx-d
or g(x)=cx-d?

- anonymous

g(f(x)) = (2x+5)-5 / 2

- anonymous

its g(x)=cx-d

- anonymous

wait im sorry i didnt include the parts

- anonymous

for part 1 it said show the work that the inverse of f(x) is g(x)

- anonymous

2nd*

- anonymous

the third part says to show my work evaluating g(x) and thats how i got the last ones

- anonymous

i got g(f(x)) = (2x+5)-5 / 2 , because i thought i would have to replace f(x) with the X in the g(x) ... if that makes any sense

- anonymous

and at the end its asking me to graph it and im lost o_o

- anonymous

what do you have to graph?
f(g(x))?

- anonymous

yes ..

- anonymous

i got this far : \[g(f(x)) = \frac{ (2x+5)-5 }{ 2 }\]

- anonymous

but im not sure how to graph it now

- anonymous

Can you type out the whole problem correctly in one box to make sure?

- anonymous

thats it....

- anonymous

tell me part 1,2,3 exactly from your assignment

- anonymous

I need to know all the parts to do the steps correctly.

- anonymous

Task 1
Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses.
f(x)=
x+a
/
b
g(x)=cxâˆ’d
Part 2. Show your work to prove that the inverse of f(x) is g(x).
Part 3. Show your work to evaluate g(f(x)).
Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.

- anonymous

And if you go to the top, thats how i did the work...

- anonymous

Part 1 Let a=5, b=2,c=2,d=5 so |dw:1440132478788:dw|
Part 2
|dw:1440132298809:dw|
|dw:1440132437924:dw|
Part 3:|dw:1440132646061:dw|
|dw:1440132696527:dw|

- anonymous

Part 4|dw:1440132750951:dw|

- anonymous

You are supposed to graph f(x), g(x) and y=x not g(fx))

- anonymous

thaaank youuuuuuuuuuuuuuuuuuuuuuu very muchh !

- anonymous

You see that f(x) and g(x) are symmetrical to the line y=x?

- anonymous

No problem!

- anonymous

yes now i understand it ! thanks alot

- anonymous

I forgot to write down the 5 values of each function, but I think you know that.
All you do is plug in 5 value into x to find y
Glad to help!

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