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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is an easy one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok first you try finding the deer population in the first year. Do you know what you would do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well as you said, the rate of increase is 3%. All you would do for the first year, is to multiply the original amount (1253) by 3% or .03

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that make sense on why you would do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay yeah that makes sense.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what did you get for your answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok good, now since the deer population is INCREASING do you have an idea on what you would do with that number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm something with the 6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll get to the 6 later. Since we did the first year, we will add 37.59 to the ORIGINAL 1253 deer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0correct. remember its INCREASING, so you will add.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! OK we just finished year 1, now since its increasing by 3% every year, you must do the same thing we just did for the next year. what do you think that is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have the right idea. You will take 1290.59 and take 3% of that number.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you take 3% of the previous year, and add that to the new population.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what level of schooling is it though? Is it possible they want you to use an exponential function? likeP= A^(r t) where P is population A is starting amount r is the rate t is the term?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or is Rstones method okay? because they will both work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is 8th year and I think they want me to write a function that represents the deer population.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that models the deer population actually.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know if they want you to use e like eulers number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah I think they want that exponential function in there because that's what the lesson is about

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well that would've helped

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill let hugh explain it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its cool man, you can do it if you like, didn't mean to hijack your help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I mean it didn't specifically say to use that, but since that was what some of the lesson talked about... I didn't know if it needed to be used

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these are questions at the end of the lessons

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0were they talking about continuous compounding ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I barely know what any of this means, I missed the class

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm nope I do think it just needs to be written as exponential function to get the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok 1 sec... lol.. dusting off my cobwebs...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my book has this function y=y(0)e^kt

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if that helps at all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When critters and bacteria multiply they use a compounding exponential function.. and the euler number. the function would look like. yah awesome... thats it..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so your y(0) is your starting population

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good, the k is the rate at which they grow.. as a decimal of 1..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then t is your term :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0term? the 6? that's the only one left

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's it.. a term of 6 years.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to be a function... then you would want a function of t... so...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f[t] = y(0) E^(k t) and you would plug in your value for y(0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and your constant for the rate of growth (k)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes starting population = y(0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you should have something that looks like f(t) = 1253 e^(0.03 t)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you ahve the correct equation.. and if you need to make it a formula instead.. then you keep the t, and set a parameter in your function for it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have a choice that is 1456. That's the closest to that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh its multipole choice?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah there's a few to pick from 1044 9134 1777 1496

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f[6] = 1253 E^(0.03 (6)) = 1500.11

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah so I guess it's all just approximate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wow that's sneaky hey ... yeah I'd go with the closest value..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In the question is subtly uses "about how many dear" so I guess it doesn't have to be exact.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats like 1252 deer hey.. I guess one died.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thanks for helping me it's really appreciated!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no worries.. good luck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you :) I understand this more thanks to you
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