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anonymous
 one year ago
(sin Θ − cos Θ)2 − (sin Θ + cos Θ)2
anonymous
 one year ago
(sin Θ − cos Θ)2 − (sin Θ + cos Θ)2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0−4sin(Θ)cos(Θ) 2 sin2 Θ cos2 Θ

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0distribute, then combine terms note : sin^2 + cos^2 = 1

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1use difference of squares, a^2  b^2 = (a+b)(ab)

midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.1\[a ^{2}  b ^{2} = (ab)(a+b)\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1where a = sin Θ − cos Θ b = sin Θ + cos Θ

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1can you do it @gabbimanges17 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus is the answer sin^2?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1nope. what do you get for (ab)? and what do you get for (a+b)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus im not sure

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[ (\sin\theta − \cos\theta)^2 − (\sin\theta + \cos\theta)^2\] \[\Big((\sin\theta − \cos\theta)+(\sin\theta + \cos\theta)\Big)\Big((\sin\theta − \cos\theta)(\sin\theta + \cos\theta)\Big)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks like they cancel each other out

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1many of the terms cancel away, but not all of them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus can you specify?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[\color{teal}{(\sin\theta − \cos\theta)}^2 − \color{orange}{(\sin\theta + \cos\theta)}^2\] \[=\Big(\color{teal}{(\sin\theta − \cos\theta)}+\color{orange}{(\sin\theta + \cos\theta)}\Big)\Big(\color{teal}{(\sin\theta − \cos\theta)}\color{orange}{(\sin\theta + \cos\theta)}\Big)\\ =\Big(\sin\theta − \cos\theta+\sin\theta + \cos\theta\Big)\Big(\sin\theta − \cos\theta\sin\theta  \cos\theta\Big)\\ = \]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[=\Big(\sin\theta +\sin\theta + \cos\theta − \cos\theta\Big)\Big(\sin\theta \sin\theta  \cos\theta− \cos\theta\Big)\\ =\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1work it out properly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what youre asking.. it looks like the last two cos dont cancel out

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[=\Big(\sin\theta +\sin\theta + \cos\theta − \cos\theta\Big)\Big(\sin\theta \sin\theta  \cos\theta− \cos\theta\Big)\\ =\Big((1+1)\sin\theta + (11)\cos\theta\Big)\Big((11)\sin\theta +(11)\cos\theta\Big)\\ =\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have me in a twist

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure about anything anymore, please can you explain in plain english

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1The expression given is a difference of squares, we used a formula we already knew for the difference of square to rearrange the expression. Then we simplified the terms in this new form, and we got ...
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