(sin Θ − cos Θ)2 − (sin Θ + cos Θ)2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

(sin Θ − cos Θ)2 − (sin Θ + cos Θ)2

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

−4sin(Θ)cos(Θ) 2 sin2 Θ cos2 Θ
distribute, then combine terms note : sin^2 + cos^2 = 1
use difference of squares, a^2 - b^2 = (a+b)(a-b)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[a ^{2} - b ^{2} = (a-b)(a+b)\]
where a = sin Θ − cos Θ b = sin Θ + cos Θ
can you do it @gabbimanges17 ?
@UnkleRhaukus is the answer sin^2?
nope. what do you get for (a-b)? and what do you get for (a+b)?
@UnkleRhaukus im not sure
\[ (\sin\theta − \cos\theta)^2 − (\sin\theta + \cos\theta)^2\] \[\Big((\sin\theta − \cos\theta)+(\sin\theta + \cos\theta)\Big)\Big((\sin\theta − \cos\theta)-(\sin\theta + \cos\theta)\Big)\]
looks like they cancel each other out
many of the terms cancel away, but not all of them
@UnkleRhaukus can you specify?
\[\color{teal}{(\sin\theta − \cos\theta)}^2 − \color{orange}{(\sin\theta + \cos\theta)}^2\] \[=\Big(\color{teal}{(\sin\theta − \cos\theta)}+\color{orange}{(\sin\theta + \cos\theta)}\Big)\Big(\color{teal}{(\sin\theta − \cos\theta)}-\color{orange}{(\sin\theta + \cos\theta)}\Big)\\ =\Big(\sin\theta − \cos\theta+\sin\theta + \cos\theta\Big)\Big(\sin\theta − \cos\theta-\sin\theta - \cos\theta\Big)\\ = \]
\[=\Big(\sin\theta +\sin\theta + \cos\theta − \cos\theta\Big)\Big(\sin\theta -\sin\theta - \cos\theta− \cos\theta\Big)\\ =\]
0
work it out properly
im not sure what youre asking.. it looks like the last two cos dont cancel out
\[=\Big(\sin\theta +\sin\theta + \cos\theta − \cos\theta\Big)\Big(\sin\theta -\sin\theta - \cos\theta− \cos\theta\Big)\\ =\Big((1+1)\sin\theta + (1-1)\cos\theta\Big)\Big((1-1)\sin\theta +(-1-1)\cos\theta\Big)\\ =\]
2?
you have me in a twist
simplify!
−4sin(Θ)cos(Θ)
are you sure?
im not sure about anything anymore, please can you explain in plain english
The expression given is a difference of squares, we used a formula we already knew for the difference of square to rearrange the expression. Then we simplified the terms in this new form, and we got ...
−4sin(Θ)cos(Θ)
good.
thank you!

Not the answer you are looking for?

Search for more explanations.

Ask your own question