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anonymous
 one year ago
Can someone PLEASE help me out with Inequality? SOS
anonymous
 one year ago
Can someone PLEASE help me out with Inequality? SOS

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[X>7 or 2<X<6 or X \le3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's the answer, and I don't understand how to do that!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factorize the top and the bottom separately first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we get (x+3)((x6) for the nominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and for the denominator we get (x7)(x+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, now, what values of x cannot work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (x6)(x+3) }{ (x7)(x+2) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you please show how to calculate from here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorru. computers being mean.. and be careful, its 7 and 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now the way I would do it, graph the quadratic you get in the numerator. See what values of x give a positive y and that's you're answer. Be careful to exclude 7 and 2 though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what I did but I didn't get the asnswer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from graphing you should get x<3 and x>6... but, since we can't have 7 you should get X<3, 6<x<7, and x>7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but that's not the answer... thanks though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 will you be savior?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440157290238:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1pick any number to the left of 3 say 4 plug x = 4 in the given inequality

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (x6)(x+3) }{ (x7)(x+2)}\] plugging x=4 gives \[\frac{ (46)(4+3) }{ (47)(4+2) }\] looks it is positive, yes ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but why would you put 4 from the first place?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1you can put any number to the left of 3 for testing since 4 is easy to work..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok, then what am I doing from here?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1since a number to the left of 3 satisfies the inequality, \(x\lt 3\) is part of the solution : dw:1440158449273:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1lets check the next interval \((3, 2)\) pick a number between 3 and 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry there's a slightly problem with the internet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I'm not following thanks though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's supposed to be a really easy question

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (x6)(x+3) }{ (x7)(x+2)}\] plugging x=2.5 gives \[\frac{ (2.56)(2.5+3) }{ (2.57)(2.5+2) }\] looks it is negative, yes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so the interval (3, 2) is not a solution : dw:1440159462256:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1to test the next interval \((2,6)\) pick some easy number between them and plug it in the inequality

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I need to plug in 4 times?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can we try 1.5 together please? I think I've got it!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1try some easy number like x=0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.10 is between 2 and 6

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (x6)(x+3) }{ (x7)(x+2)}\] plugging x=0 gives \[\frac{ (06)(0+3) }{ (07)(0+2) }\] looks it is positive, yes ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so between 2 and 6 it's ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08 is negative then no

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and 7.5 is fine likewise

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what we get is that 3>x, 2<x<6 and x>7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you're brilliant! thank you so so much!!!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.07.5 isn't good right

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440159894339:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1double check with wolfram http://www.wolframalpha.com/input/?i=solve+%28x%5E23x18%29%2F%28x%5E25x14%29%3E%3D0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1np, the basic procedure for solving rational inequalities is : 1) factor both numerator and denomiantor 2) find the x values where the numerator or denominator equal 0 3) plot them on number line 4) pick a number in each interval and test the inequality

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 is there any easier way to solve it?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1hmm i can't think of any other easy way to solve it.. post it again and see what others have to say..
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