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Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).
the least value for g(x) as seen from the table is at (-1,0)

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Other answers:

now you need to find the coordinates of the minimum value of 4x^2 + 8x + 1 do you know how to do that ?
No. I am just learning it.
you can do it by converting to vertex form is that what you are learning?
I dont know what grade you are working at
the general form for the vertex is a(x - b)^2 + c
you perform what is called 'complete the square' on the terms in x^2 and x
ok.
??
ok so the answer is C?
4x2 + 8x + 1 = 4(x^2 + 2x + 1/4) = 4 [(x + 1)^2 - 3/4] so the minimum values is at the coordinates (-1 , 4*-3/4) = (-1,-3)
so compare this wit (-1,0) and you'll see which has minimum value
- the second coordinate will give you the minimum value (because second cood is the value of the function)
ok?
So the answer is D? Correct?
No it cant be D because the coordinates re not (0,2)
compare (-1,0) and (-1,-3) thats all you need do

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