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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).

  2. anonymous
    • one year ago
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    @welshfella

  3. welshfella
    • one year ago
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    the least value for g(x) as seen from the table is at (-1,0)

  4. welshfella
    • one year ago
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    now you need to find the coordinates of the minimum value of 4x^2 + 8x + 1 do you know how to do that ?

  5. anonymous
    • one year ago
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    No. I am just learning it.

  6. welshfella
    • one year ago
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    you can do it by converting to vertex form is that what you are learning?

  7. welshfella
    • one year ago
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    I dont know what grade you are working at

  8. welshfella
    • one year ago
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    the general form for the vertex is a(x - b)^2 + c

  9. welshfella
    • one year ago
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    you perform what is called 'complete the square' on the terms in x^2 and x

  10. anonymous
    • one year ago
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    ok.

  11. welshfella
    • one year ago
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    ??

  12. anonymous
    • one year ago
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    ok so the answer is C?

  13. welshfella
    • one year ago
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    4x2 + 8x + 1 = 4(x^2 + 2x + 1/4) = 4 [(x + 1)^2 - 3/4] so the minimum values is at the coordinates (-1 , 4*-3/4) = (-1,-3)

  14. welshfella
    • one year ago
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    so compare this wit (-1,0) and you'll see which has minimum value

  15. welshfella
    • one year ago
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    - the second coordinate will give you the minimum value (because second cood is the value of the function)

  16. welshfella
    • one year ago
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    ok?

  17. anonymous
    • one year ago
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    So the answer is D? Correct?

  18. welshfella
    • one year ago
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    No it cant be D because the coordinates re not (0,2)

  19. welshfella
    • one year ago
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    compare (-1,0) and (-1,-3) thats all you need do

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