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anonymous
 one year ago
Hi!
I have to put down this formula y = ab^x and I need help with it.
anonymous
 one year ago
Hi! I have to put down this formula y = ab^x and I need help with it.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes you are. Next, I would divide the second equation by the first equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 4 by 16 or the whole things?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0IN order to maintain equality you have to divide both sides. Like this:\[\frac{ 16 }{ 4 } = \frac{ ab^{3} }{ ab^{1} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, carrying out the division above, you'll get\[4 = b^{2} = \frac{1}{b^2}\]Can you solve for b?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0um sorry I don't know what exactly to do... i'm trying to think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's back up a bit and make sure you're OK with the division.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You had\[\frac{ 16 }{ 4 } = \frac{ ab^{3} }{ ab^{1} }\]The left hand side is easy. On the right hand side, the a's will cancel out, leaving\[4=\frac{ b^{3} }{ b^{1} }\]Are you OK with it so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are correct, b = 1/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay yeah I see duh lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're doing a good job. Now, substitute b=1/2 into either of the given equations and solve for a.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The first one might be easier to work with\[4=a \left( \frac{ 1 }{ 2 } \right)^{1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would the second equation be set up? same thing just replace the 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, you don't really need it. You already have the answer, but if you chose to work with the second equation instead, it would look like\[16 = a \left( \frac{ 1 }{ 2 } \right)^{3}\]and you get the same answer, a=2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or don't we have to do 16/4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so what's next?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You need one more step: reject the value b =1/2 Since \(b^2=\dfrac{1}{4}\\b=\pm\sqrt{\dfrac{1}{4}}=\pm\dfrac{1}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have a and b. Put them into the general function\[y=ab^x\]What do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excellent. Well done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Whichever you teacher (or courseware) prefers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think he wants decimal. Anyways merci beaucoup! I appreciate this so much. You rock
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