anonymous
  • anonymous
Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at y = ±5/6* x.
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at y = ±5/6* x.
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Plasmataco
  • Plasmataco
... I'll try but no garentees
anonymous
  • anonymous
No problem! Atleast if you can try or get someone to help you too
Plasmataco
  • Plasmataco
It's center is at the origin so...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Plasmataco
  • Plasmataco
Ok... U listening?
Plasmataco
  • Plasmataco
What u got to do is put the x in the coordinates of the vertices in for the asymptote equation.
Plasmataco
  • Plasmataco
So plug 10 in to get y=50/6
anonymous
  • anonymous
is this vertical or horiztonal though
Plasmataco
  • Plasmataco
.
Plasmataco
  • Plasmataco
Hang on.
Plasmataco
  • Plasmataco
Because the center is (0,0), it makes thing a lot easier
anonymous
  • anonymous
Oh okay
Plasmataco
  • Plasmataco
The equation is ((X-g)/a)-((y-f)/b)=1
anonymous
  • anonymous
okay yeah I have that
Plasmataco
  • Plasmataco
(G,f) is the center of the hyperbola in which case (0,0) so we can cancel those out to get (X squared)/a-(y squared)/b
Plasmataco
  • Plasmataco
My first equation is wrong. I forgot the power 2 after(x-g) and (y-f) sry 😓
anonymous
  • anonymous
okay yeah I was gonna correct that
Plasmataco
  • Plasmataco
A is the x part of the vertice so 10. B is what we solved earlier with the asymptote.
anonymous
  • anonymous
wait what is b?
Plasmataco
  • Plasmataco
So we get (x squared)/10-(y squared times 6)/50=1
Plasmataco
  • Plasmataco
The 6th comment
Plasmataco
  • Plasmataco
No wait the answer is (x/10) squared-(6y/50) squared=1
Plasmataco
  • Plasmataco
Forgot another pair of squares at the denominator
Plasmataco
  • Plasmataco
Here's the link I used
Plasmataco
  • Plasmataco
http://www.endmemo.com/geometry/hyperbola.php
Plasmataco
  • Plasmataco
Plasmataco
  • Plasmataco
Ok well. I gotta go sry
Plasmataco
  • Plasmataco
I hoped I helped
anonymous
  • anonymous
Yeah sorry I been trying to figure this out with my notes but you helped so much more thank you so much

Looking for something else?

Not the answer you are looking for? Search for more explanations.