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... I'll try but no garentees
No problem! Atleast if you can try or get someone to help you too
It's center is at the origin so...
Ok... U listening?
What u got to do is put the x in the coordinates of the vertices in for the asymptote equation.
So plug 10 in to get y=50/6
is this vertical or horiztonal though
Because the center is (0,0), it makes thing a lot easier
The equation is ((X-g)/a)-((y-f)/b)=1
okay yeah I have that
(G,f) is the center of the hyperbola in which case (0,0) so we can cancel those out to get (X squared)/a-(y squared)/b
My first equation is wrong. I forgot the power 2 after(x-g) and (y-f) sry 😓
okay yeah I was gonna correct that
A is the x part of the vertice so 10. B is what we solved earlier with the asymptote.
wait what is b?
So we get (x squared)/10-(y squared times 6)/50=1
The 6th comment
No wait the answer is (x/10) squared-(6y/50) squared=1
Forgot another pair of squares at the denominator
Here's the link I used
Ok well. I gotta go sry
I hoped I helped
Yeah sorry I been trying to figure this out with my notes but you helped so much more thank you so much