A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

A solid disk and a solid sphere each of mass M and radius R are released at the same time from the top of an inclined plane. which object will reach the bottom first? Justify your answer. Show complete derivation.

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dont go away i am going to solve this problem..

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1440170882815:dw|

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for normal reaction, N= mgcosa

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for motion down the inclined plane, F= mg sina - f ............(1)

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    since friction prevents slipping and frictional force is causing rotation with angular acceleration @ thus torque, T = f*R = I*@

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f= I*@/R = I*a/R^2

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    m*a=mgsina - I*a/R^2

  8. IrishBoy123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if frictionless [ you did not specify], then same but if they are rolling, the cylinder will be slower as has a greater I [as it is more "spread out" about the rotating axis] to prove that, personally i'd use energy conservation for this rather than forces as its a lot less fiddly

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a= gsina - I*a/R^2

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now if u put the value of moment of inertia for sphere and disc, u get the the linear acc downward...

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you guys :D

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do u know what is moment of inertia for sphere and disc....

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    greater the linear acc. more faster the object reaches the ground faster.....

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    got it?

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes :)

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes we've already had an experiment about this one. thank you again :)

  17. IrishBoy123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    good job @lall

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks! @IrishBoy123

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    their moment of inertia can be calculated mathematically.....

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.