anonymous
  • anonymous
I need help translating graphs.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
try using this website type the first equation on line on look at it type the seccond equation on line two and see how it changedvhttps://www.desmos.com/calculator
anonymous
  • anonymous
it will graph it for you
anonymous
  • anonymous
I found that website but I guess it shifts down or right if you tilt your head to the left lol idk

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
lol ill try typing it in
anonymous
  • anonymous
is five on the top then or is it on its owm because you put that ^ so im not sure
anonymous
  • anonymous
the 5's are seperate from /2s
anonymous
  • anonymous
and the -3 in the first one is on it's own too
Michele_Laino
  • Michele_Laino
hint: if we set x=0, into this equation: y= -1/2(5)^x -3 what do we get?
Michele_Laino
  • Michele_Laino
|dw:1440171681195:dw|
anonymous
  • anonymous
so like y=-1/2(5)^0 -3 @Michele_Laino
anonymous
  • anonymous
oh I see your graph now
anonymous
  • anonymous
so it has to be reflected across y-axix 3 units to the right? @Michele_Laino
anonymous
  • anonymous
*axis
Michele_Laino
  • Michele_Laino
your graph is reflected with respect to the x-axis, and since: y= -1/2(5)^x -3= -4 when x=0, then we have: |dw:1440171970254:dw|
anonymous
  • anonymous
okay so x-axis I see.
Michele_Laino
  • Michele_Laino
sorry I have made an error: here is the right graph: |dw:1440172177891:dw|
Michele_Laino
  • Michele_Laino
since: at x=0, we have: \[y = - \frac{1}{2}{5^0} - 3 = - \frac{1}{2} - 3 = - \frac{7}{2}\]
anonymous
  • anonymous
okay so I'm not sure how to tell if it goes down or right now, I think I was wrong
Michele_Laino
  • Michele_Laino
as you can see, the shifting was down with respect to the graph of the function: y=(1/2)5^x
Michele_Laino
  • Michele_Laino
nevertheless that shifting was about \[\frac{1}{2} - \left( { - \frac{7}{2}} \right) = \frac{1}{2} + \frac{7}{2} = \frac{8}{2} = 4\] units, with respect to the graph of: y=(1/2)5^x
anonymous
  • anonymous
yeah okay I see that it's down x-axis reflected 3 units down. I'm going to have to go back and reread all that you typed. I super super appreciate all that work from you. You rock merci beaucoup!
Michele_Laino
  • Michele_Laino
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.