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anonymous
 one year ago
A quadratic equation is shown below:
9x2 − 36x + 36 = 0
Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)
Part B: Solve 2x2 − 9x + 7 = 0 using an appropriate method. Show the steps of your work and explain why you chose the method used. (5 points)
anonymous
 one year ago
A quadratic equation is shown below: 9x2 − 36x + 36 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points) Part B: Solve 2x2 − 9x + 7 = 0 using an appropriate method. Show the steps of your work and explain why you chose the method used. (5 points)

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freckles
 one year ago
Best ResponseYou've already chosen the best response.2So part A sounds like it i asking you to find the discriminant

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[ax^2+bx+c=0 \\ \text{ then the discriminant is } b^24ac\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I already have part A I just need Part B.

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\text{ if } b^24ac>0 \text{ then you have two real solutions } \\ \text{ if } b^24ac=0 \text{ then you have one real solution (multiplicity 2)} \\ \text{ if } b^24ac<0 \text{ then you have two complex solutions }\] (assuming of course that a,b,c are real coefficients)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0for part B you can use factorisation

freckles
 one year ago
Best ResponseYou've already chosen the best response.2Well you can use quadratic formula. Or completing the square.

freckles
 one year ago
Best ResponseYou've already chosen the best response.2that would be one solution

freckles
 one year ago
Best ResponseYou've already chosen the best response.2there is another solution

freckles
 one year ago
Best ResponseYou've already chosen the best response.2And we are talking about 2x^29x+7=0 right?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2so if you figured out x=1 is solution then you know that x1 is a factor (x1)( )=2x^29x+7 what goes in then second pair of ( )

freckles
 one year ago
Best ResponseYou've already chosen the best response.2you know that x times what is equal to 2x^2? and that 1 times what is equal to 7?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes but what about the other question x times what gives you 2x^2

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[x \cdot 2x=2x^2 \\ 1 \cdot (7)=7 \\ \text{ and the middle term will be } 2x7x \text{ which is indeed } 9x\] \[(x1)(2x7)=2x^29x+7 \\ \\ \text{ so you have that the equation } 2x^29x+7=0 \\ \text{ is equivalent to the equation } (x1)(2x7)=0 \\ \text{ which is equivalent to solving the conjunction } x1=0 \text{ or } 2x7=0\]
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