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- anonymous

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 4 inches, and the height of the cone is 6 inches. If the diameter of the bubble gum is 0.8 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice?

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- anonymous

- jamiebookeater

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- anonymous

1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.43)
1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.43)
1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.83)
1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.83)

- anonymous

- anonymous

you want to subtract the volume of the sphere from the volume of the cone.
cone: \[V=\frac{ \pi }{ 3 }\pi r^2h\]
r = radius, h = height
sphere: \[V=\frac{ 4 }{ 3 }\pi r^3\]
r = radius

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- anonymous

Ok so V of cone=pi/3pi4^2x6

- anonymous

and V of sphere= 4/3pi4^3?

- anonymous

the cone is right.
The sphere should be (4/3)π(0.4)^3

- anonymous

Oh alright, so then i subtract pi/3pi4^2x6-(4/3)pi(o.4)^3

- anonymous

yes

- anonymous

wait hold up. I put an extra π in the cone equation by mistake. There should only be one π there

- anonymous

so it would pi over 3? or pi r squared?

- anonymous

it would be pi*

- anonymous

- anonymous

It's (π/3)r²h so (π/3)(4^2)(6)

- anonymous

I got 66.87

- anonymous

No wait sorry

- anonymous

that's not what they're asking for lol

- anonymous

yeah, actually looking at your choices they just want you to set it up, not solve for a number

- anonymous

Yeah my bad, so the answer would be the 2nd option then

- anonymous

1 over 3(3.14)(4^2)(6) − 4 over 3(3.14)(0.4^3)

- anonymous

yes

- anonymous

alright thanks lol i have this super complex question if u can solve it i will be eternally grateful!!

- anonymous

i'll give it a try

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