one of the zeros of the function f(x)=x^4+2x^3-13x^2-38x-24 is x=-3, find the other zeros of the function

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

one of the zeros of the function f(x)=x^4+2x^3-13x^2-38x-24 is x=-3, find the other zeros of the function

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

obvious approach long divide \(x^4+2x^3-13x^2-38x-24\) by \(x+3\)
1 Attachment
@IrishBoy123 could you use synthetic division?
idgi

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

of course, you can do anything you like i am starting to think that this looks like it needs the Rational Root Theorem, despite the bad clues that were left lying around In which case, i summon the master: @welshfella
+/- 1 , +/- 2 +/- 4 are some of the possible roots
f!1) = not = 0 f(-1) = 0 so -1 is one root
you could now divide the function by (x + 3)( x + 1) to get another quadratic which you can solve
or compute f(2) f(-2,) f(4), f(-4)
the first option would probably be the quickest
use synthetic division

Not the answer you are looking for?

Search for more explanations.

Ask your own question