anonymous
  • anonymous
one of the zeros of the function f(x)=x^4+2x^3-13x^2-38x-24 is x=-3, find the other zeros of the function
Mathematics
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SOLVED
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katieb
  • katieb
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IrishBoy123
  • IrishBoy123
obvious approach long divide \(x^4+2x^3-13x^2-38x-24\) by \(x+3\)
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anonymous
  • anonymous
@IrishBoy123 could you use synthetic division?
anonymous
  • anonymous
idgi

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IrishBoy123
  • IrishBoy123
of course, you can do anything you like i am starting to think that this looks like it needs the Rational Root Theorem, despite the bad clues that were left lying around In which case, i summon the master: @welshfella
welshfella
  • welshfella
+/- 1 , +/- 2 +/- 4 are some of the possible roots
welshfella
  • welshfella
f!1) = not = 0 f(-1) = 0 so -1 is one root
welshfella
  • welshfella
you could now divide the function by (x + 3)( x + 1) to get another quadratic which you can solve
welshfella
  • welshfella
or compute f(2) f(-2,) f(4), f(-4)
welshfella
  • welshfella
the first option would probably be the quickest
welshfella
  • welshfella
use synthetic division

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