anonymous
  • anonymous
For the graph below, what should the domain be so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200 −5 ≤ x ≤ 20 0 ≤ x ≤ 15 x ≥ 0 All real numbers
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
http://prntscr.com/87cqe0
anonymous
  • anonymous
@Michele_Laino
Michele_Laino
  • Michele_Laino
hint: from your graph, I see that: f(0)= 200, f(15)=200, and fo r all point x between 0 and 15, is f(x)>200

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Michele_Laino
  • Michele_Laino
oopss. for all points*
anonymous
  • anonymous
I am sorry i am still confused.
Michele_Laino
  • Michele_Laino
|dw:1440187581388:dw|
anonymous
  • anonymous
Okay.
Michele_Laino
  • Michele_Laino
at x=0, f(x) = 200 right?
anonymous
  • anonymous
Right.
Michele_Laino
  • Michele_Laino
furthermore also at x=15, f(x)= 200
anonymous
  • anonymous
Okay :]
Michele_Laino
  • Michele_Laino
and if x>0 and x<15, f(x) is > 200
anonymous
  • anonymous
0 ≤ x ≤ 15
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
Is that all for my answer?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
Can you help with 1 more? The following graph shows the functions f(x) and g(x): graph of function f of x equals x squared and graph of function g of x equals x squared plus 5 The function g(x) is obtained by adding _______ to f(x). (only input integers) Numerical Answers Expected! Answer for Blank 1:
Michele_Laino
  • Michele_Laino
we have: \[\Large \begin{gathered} f\left( x \right) = {x^2} \hfill \\ g\left( x \right) = {x^2} + 5 \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
now I replace x^2 with f(x) into the expression for g(x), and I can write this: \[\Large g\left( x \right) = f\left( x \right) + 5\]
Michele_Laino
  • Michele_Laino
so what can you conclude?
anonymous
  • anonymous
Sorry i am confused.
Michele_Laino
  • Michele_Laino
the expression of f(x) and g(x) are correct, right?
Michele_Laino
  • Michele_Laino
expressions*
anonymous
  • anonymous
Yes?
Michele_Laino
  • Michele_Laino
ok! now I can rewrite the first equation as below: \[\Large {x^2} = f\left( x \right)\]
anonymous
  • anonymous
ok.
Michele_Laino
  • Michele_Laino
then, I replace x^2 with f(x), into the expression for g(x), so I get this equation: \[\Large g\left( x \right) = f\left( x \right) + 5\]
anonymous
  • anonymous
Okay :]
Michele_Laino
  • Michele_Laino
ok! now, the geometrical meaning of that equation is: |dw:1440188519007:dw|
Michele_Laino
  • Michele_Laino
|dw:1440188632785:dw|
Michele_Laino
  • Michele_Laino
so, what is the requested number?
anonymous
  • anonymous
5?
Michele_Laino
  • Michele_Laino
correct! since the graph of g(x), as you can see from my drawing, it is shifted up by 5 units with respect to the graph of f(x)
anonymous
  • anonymous
Thank you!!!!!!!
Michele_Laino
  • Michele_Laino
:)

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