anonymous
  • anonymous
im new hi (moderators delete this please :) and my other question thanks)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zzr0ck3r
  • zzr0ck3r
well they tell you that v = 50 So what does the equation look like now?
zzr0ck3r
  • zzr0ck3r
ok then they tell us that it starts off at 90 What do you get at the start of time? I.e. what do you get when \(t=0\)?
zzr0ck3r
  • zzr0ck3r
put in \(t=0\)

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zzr0ck3r
  • zzr0ck3r
nono, so if we let \(t=0\) into the function we get \(s\) correct?
zzr0ck3r
  • zzr0ck3r
right, and they told us that the intial height is 90, so s=90. make sense?
zzr0ck3r
  • zzr0ck3r
so what is the function?
zzr0ck3r
  • zzr0ck3r
nono, ok before we can start to answer the question we had to figure out what \(v\) and \(s\) are. Now we have done that and we have our function is \[H(t) -16t^2+50t+90\] Are you with me?
zzr0ck3r
  • zzr0ck3r
Now we can start to actually answer the question.
zzr0ck3r
  • zzr0ck3r
Ok part A wants to know \(t\) when the thing hits the ground. What is the height when something hits the ground?
zzr0ck3r
  • zzr0ck3r
ok so we need to solve \[-16t^2+50t+90=0\] Can you do that?
zzr0ck3r
  • zzr0ck3r
I am not sure if that is correct, but you can check that. Ok notice that since we are dealing with time, that we would only take the positive answer. That is part A. For part B, do you know how to find the vertex?
zzr0ck3r
  • zzr0ck3r
the \(x\) coordinate of the vertex of the function \(ax^2+bx+c\) is \(x=\dfrac{-b}{2a}\).
zzr0ck3r
  • zzr0ck3r
what do you get?
zzr0ck3r
  • zzr0ck3r
what is \(a\) and \(b\) in your equation? \(ax^2+bx+c\)?
zzr0ck3r
  • zzr0ck3r
nono \(-16x^2+50x+90\) \( \ \ \ ax^2+bx+c\) What is \(a\)?
zzr0ck3r
  • zzr0ck3r
correct, ok so what is \(\dfrac{-b}{2a}\)?
zzr0ck3r
  • zzr0ck3r
2*-16 = 100?
zzr0ck3r
  • zzr0ck3r
correct, now plug that into the equation to get the height.
zzr0ck3r
  • zzr0ck3r
I am not responsible for you failing a class. I also highly doubt that getting help on one question will change you from a failing grade to passing.
zzr0ck3r
  • zzr0ck3r
so plug in -25/16 into the function and that will give you the max height.
zzr0ck3r
  • zzr0ck3r
err 25/16

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