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anonymous

  • one year ago

help please!

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  1. anonymous
    • one year ago
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    At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 8 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color? 8 over 32 multiplied by 8 over 31 8 over 32 plus 8 over 31 8 over 32 plus 7 over 31 8 over 32 multiplied by 7 over 31

  2. anonymous
    • one year ago
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    8 over 32 plus 7 over 31

  3. mathstudent55
    • one year ago
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    The probability of the two events happening is the product of the probability of each event. Product means multiplication.

  4. mathstudent55
    • one year ago
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    There are 4 colors and 8 boxes of each color. That means there are 32 boxes altogether. The winner is the first to get a box. When he gets a box, his box is picked out of the 32. Since there are 8 white boxes, the probability of picking a white box for the winner is P(white for winner) = 8/32 Once the winner got a white box, now there are 31 boxes left and of which 7 are white. Now you take a box for the second place. P(white for second place) = 7/31 To find the final answer, MULTIPLY the two individual probabilities.

  5. anonymous
    • one year ago
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    i got 56/124

  6. anonymous
    • one year ago
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    @mathstudent55

  7. anonymous
    • one year ago
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    so is it d?

  8. mathstudent55
    • one year ago
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    Yes, you are correct. Like I wrote above, you multiply the probabilities, not add them.

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