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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 8 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color? 8 over 32 multiplied by 8 over 31 8 over 32 plus 8 over 31 8 over 32 plus 7 over 31 8 over 32 multiplied by 7 over 31
8 over 32 plus 7 over 31
The probability of the two events happening is the product of the probability of each event. Product means multiplication.

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There are 4 colors and 8 boxes of each color. That means there are 32 boxes altogether. The winner is the first to get a box. When he gets a box, his box is picked out of the 32. Since there are 8 white boxes, the probability of picking a white box for the winner is P(white for winner) = 8/32 Once the winner got a white box, now there are 31 boxes left and of which 7 are white. Now you take a box for the second place. P(white for second place) = 7/31 To find the final answer, MULTIPLY the two individual probabilities.
i got 56/124
so is it d?
Yes, you are correct. Like I wrote above, you multiply the probabilities, not add them.

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