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mathmath333

  • one year ago

Counting Problem

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{Their are 10 points on Line 1 and 11 points on line 2.}\hspace{.33em}\\~\\ & \normalsize \text{How many lines are possible if the two lines are parallel.}\hspace{.33em}\\~\\ \end{align}}\)

  2. steve816
    • one year ago
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    10*11=110 possible combinations!

  3. mathmath333
    • one year ago
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    Iwsimqwerty

  4. ytrewqmiswi
    • one year ago
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    |dw:1440196179245:dw|

  5. mathmath333
    • one year ago
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    u simply multiplied 10*11

  6. ytrewqmiswi
    • one year ago
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    me?

  7. mathmath333
    • one year ago
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    no

  8. ytrewqmiswi
    • one year ago
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    :)

  9. mathmath333
    • one year ago
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    this is given as answer \(\binom{10}{2}*\binom{11}{1}+\binom{10}{1}*\binom{11}{2}\)

  10. mathmath333
    • one year ago
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    lol it is greater than imqueryy's answer

  11. ytrewqmiswi
    • one year ago
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    :D lemme see it again :)

  12. ytrewqmiswi
    • one year ago
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    lol i read that cmnt above drawin nw XD u probably won't get that its me if i wuldn't have set my pfp :D

  13. mathmath333
    • one year ago
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    no i ur strange name imqueerty busted u

  14. ytrewqmiswi
    • one year ago
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    hahaha :D

  15. mathmath333
    • one year ago
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    |dw:1440197305564:dw|

  16. ytrewqmiswi
    • one year ago
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    can u think of any other way to connect those points?

  17. ytrewqmiswi
    • one year ago
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    i think that the solution is missing - nd it wuld be like ->\[\left( \frac{ 10 }{ 2 } \right)\left( \frac{ 11 }{ 1 } \right)+\left( \frac{ 10 }{ 1 } \right)\left( \frac{ 11 }{ 2 } \right)\] :D

  18. ytrewqmiswi
    • one year ago
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    @dan815

  19. geerky42
    • one year ago
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    I think this question is ambiguous. Two line being parallel to each other is depend on placement of points on Line 1 and Line 2.

  20. mathmath333
    • one year ago
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    I think this question is not ambiguous.

  21. geerky42
    • one year ago
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    Then that mean the definition of parallel isn't as what I think it is. Either way, I can't help, sorry.

  22. mathmath333
    • one year ago
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    |dw:1440198692921:dw|

  23. ytrewqmiswi
    • one year ago
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    :) i like ur pfp lol

  24. anonymous
    • one year ago
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    that counts the number of triangles formed by those points

  25. anonymous
    • one year ago
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    not the number of lines; for that, @ytrewqmiswi is correct

  26. mathmath333
    • one year ago
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    ok

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