Counting Problem

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\(\large \color{black}{\begin{align} & \normalsize \text{Their are 10 points on Line 1 and 11 points on line 2.}\hspace{.33em}\\~\\ & \normalsize \text{How many lines are possible if the two lines are parallel.}\hspace{.33em}\\~\\ \end{align}}\)
10*11=110 possible combinations!
Iwsimqwerty

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|dw:1440196179245:dw|
u simply multiplied 10*11
me?
no
:)
this is given as answer \(\binom{10}{2}*\binom{11}{1}+\binom{10}{1}*\binom{11}{2}\)
lol it is greater than imqueryy's answer
:D lemme see it again :)
lol i read that cmnt above drawin nw XD u probably won't get that its me if i wuldn't have set my pfp :D
no i ur strange name imqueerty busted u
hahaha :D
|dw:1440197305564:dw|
can u think of any other way to connect those points?
i think that the solution is missing - nd it wuld be like ->\[\left( \frac{ 10 }{ 2 } \right)\left( \frac{ 11 }{ 1 } \right)+\left( \frac{ 10 }{ 1 } \right)\left( \frac{ 11 }{ 2 } \right)\] :D
I think this question is ambiguous. Two line being parallel to each other is depend on placement of points on Line 1 and Line 2.
I think this question is not ambiguous.
Then that mean the definition of parallel isn't as what I think it is. Either way, I can't help, sorry.
|dw:1440198692921:dw|
:) i like ur pfp lol
that counts the number of triangles formed by those points
not the number of lines; for that, @ytrewqmiswi is correct
ok

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