anonymous
  • anonymous
Which of the following world be an acceptable first step in simplifying the expression tanx/(1+secx)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
your thoughts?
anonymous
  • anonymous
I read through the notes like 10 times and still don't understand

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More answers

jim_thompson5910
  • jim_thompson5910
|dw:1440198581765:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440198631242:dw|
anonymous
  • anonymous
isn't it eliminating the denominator ?
jim_thompson5910
  • jim_thompson5910
hint: think of the difference of squares formula
anonymous
  • anonymous
the (b/2)^2 ?
jim_thompson5910
  • jim_thompson5910
You've seen this formula before hopefully a^2 - b^2 = (a-b)(a+b)
anonymous
  • anonymous
oh yeah. I'm used to the (a-b)2 but I know what you're talking about
anonymous
  • anonymous
(a-b)^2 *
jim_thompson5910
  • jim_thompson5910
so the idea is that we multiply top and bottom by 1-sec(x), then we get this |dw:1440198998954:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440199030582:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440199066043:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440199086975:dw|
jim_thompson5910
  • jim_thompson5910
what is 1-sec^2 equal to?
anonymous
  • anonymous
umm , the first number to pop up in my head was 1 lol
jim_thompson5910
  • jim_thompson5910
nope
jim_thompson5910
  • jim_thompson5910
look at this identity sheet http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
jim_thompson5910
  • jim_thompson5910
look on page 2 where it says "Pythagorean Identities"
anonymous
  • anonymous
tan^2 theta ?
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
|dw:1440199398015:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1440199419561:dw|
jim_thompson5910
  • jim_thompson5910
so the original expression is equivalent to \[\Large \frac{1-\sec(x)}{\tan(x)}\]
anonymous
  • anonymous
okay, so the answer would be a ?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
thank you!
jim_thompson5910
  • jim_thompson5910
no problem

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