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anonymous

  • one year ago

WILL AWARD MEDAL How do you solve the inequality (x^2)(e^x) ln x > 0?? @nincompoop @Nnesha @zepdrix @jagr2713

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  1. zzr0ck3r
    • one year ago
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    well \(e^x>0\) for all \(x\), \(x^2>0\) for all \(x\ne 0\) and \(\ln(x)>0\) for all \(x>1\). So ?

  2. zzr0ck3r
    • one year ago
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    hint: the \(ln(x)\) factor trumps them all.

  3. anonymous
    • one year ago
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    sorry i don't really understand where this is going.

  4. anonymous
    • one year ago
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    @zzr0ck3r

  5. anonymous
    • one year ago
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    These are things we can do without affecting the direction of the inequality: Add (or subtract) a number from both sides. Multiply (or divide) both sides by a positive number. Simplify a side. Hoped this helped :)

  6. zzr0ck3r
    • one year ago
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    What I am saying is that \(x^2e^x\ln(x)>0 \iff \ln(x)>0\iff x>1\)

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