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NaviAn

  • one year ago

Help me please, I have to solve an integral by substitution!

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  1. NAVIAN
    • one year ago
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  2. IrishBoy123
    • one year ago
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    i'd just slog it out with \(u = e^x + 1 , \ e^x = u-1, \ du = e^x .dx \implies dx = \frac{du}{u-1}\) leaving \(\int \frac{u-2}{u} \frac{1}{u-1} \ du\) and some partial fractions to fiddle about with then remember to transform it back with \(u = e^x + 1\)

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