AmTran_Bus
  • AmTran_Bus
More complex number help
Mathematics
chestercat
  • chestercat
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AmTran_Bus
  • AmTran_Bus
|dw:1440207992331:dw|
AmTran_Bus
  • AmTran_Bus
Find the real and imaginary parts, prob Euler's again
dan815
  • dan815
|dw:1440208031147:dw|

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More answers

dan815
  • dan815
you can either write both of them in polar like so, or change the e^-ipi/2 to rectangular
AmTran_Bus
  • AmTran_Bus
Oh gosh. Soln man says i(sqrt(2)+2i) sin(-pi/2) = 2-isqrt(2)
dan815
  • dan815
|dw:1440208108377:dw|
dan815
  • dan815
ok that means they put it rectangular which is probaly better
AmTran_Bus
  • AmTran_Bus
That is the way I have worked the other problems.
dan815
  • dan815
|dw:1440208219136:dw|
dan815
  • dan815
much simpler lol
AmTran_Bus
  • AmTran_Bus
Where did the (-i) come from?
dan815
  • dan815
|dw:1440208320781:dw|
dan815
  • dan815
|dw:1440208347541:dw|
dan815
  • dan815
|dw:1440208362546:dw|
AmTran_Bus
  • AmTran_Bus
Oh since cos -pi/2 is 0 and sin of -pi/2 is -1?
AmTran_Bus
  • AmTran_Bus
lol good timing.
dan815
  • dan815
you should get used to think about e^itheta as vectors
dan815
  • dan815
R*e^itheta means theta is the angle and R is the radius
AmTran_Bus
  • AmTran_Bus
Ok, so that takes care of some, but what about the rest|dw:1440208469040:dw|
dan815
  • dan815
multiply
AmTran_Bus
  • AmTran_Bus
Like I guess I just cant put it all toghether.
AmTran_Bus
  • AmTran_Bus
Oh, just by the (sqrt(2)+2i)?
dan815
  • dan815
|dw:1440208530346:dw|
AmTran_Bus
  • AmTran_Bus
Perfect. I'm gonna re work it on my own and see if I really got it.
dan815
  • dan815
|dw:1440208587135:dw|
dan815
  • dan815
ok good luck
AmTran_Bus
  • AmTran_Bus
you are the absolute best.

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