## AmTran_Bus one year ago More complex number help

1. AmTran_Bus

|dw:1440207992331:dw|

2. AmTran_Bus

Find the real and imaginary parts, prob Euler's again

3. dan815

|dw:1440208031147:dw|

4. dan815

you can either write both of them in polar like so, or change the e^-ipi/2 to rectangular

5. AmTran_Bus

Oh gosh. Soln man says i(sqrt(2)+2i) sin(-pi/2) = 2-isqrt(2)

6. dan815

|dw:1440208108377:dw|

7. dan815

ok that means they put it rectangular which is probaly better

8. AmTran_Bus

That is the way I have worked the other problems.

9. dan815

|dw:1440208219136:dw|

10. dan815

much simpler lol

11. AmTran_Bus

Where did the (-i) come from?

12. dan815

|dw:1440208320781:dw|

13. dan815

|dw:1440208347541:dw|

14. dan815

|dw:1440208362546:dw|

15. AmTran_Bus

Oh since cos -pi/2 is 0 and sin of -pi/2 is -1?

16. AmTran_Bus

lol good timing.

17. dan815

you should get used to think about e^itheta as vectors

18. dan815

R*e^itheta means theta is the angle and R is the radius

19. AmTran_Bus

Ok, so that takes care of some, but what about the rest|dw:1440208469040:dw|

20. dan815

multiply

21. AmTran_Bus

Like I guess I just cant put it all toghether.

22. AmTran_Bus

Oh, just by the (sqrt(2)+2i)?

23. dan815

|dw:1440208530346:dw|

24. AmTran_Bus

Perfect. I'm gonna re work it on my own and see if I really got it.

25. dan815

|dw:1440208587135:dw|

26. dan815

ok good luck

27. AmTran_Bus

you are the absolute best.