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AmTran_Bus
 one year ago
More complex number help
AmTran_Bus
 one year ago
More complex number help

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440207992331:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Find the real and imaginary parts, prob Euler's again

dan815
 one year ago
Best ResponseYou've already chosen the best response.2you can either write both of them in polar like so, or change the e^ipi/2 to rectangular

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Oh gosh. Soln man says i(sqrt(2)+2i) sin(pi/2) = 2isqrt(2)

dan815
 one year ago
Best ResponseYou've already chosen the best response.2ok that means they put it rectangular which is probaly better

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1That is the way I have worked the other problems.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Where did the (i) come from?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Oh since cos pi/2 is 0 and sin of pi/2 is 1?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2you should get used to think about e^itheta as vectors

dan815
 one year ago
Best ResponseYou've already chosen the best response.2R*e^itheta means theta is the angle and R is the radius

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Ok, so that takes care of some, but what about the restdw:1440208469040:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Like I guess I just cant put it all toghether.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Oh, just by the (sqrt(2)+2i)?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1Perfect. I'm gonna re work it on my own and see if I really got it.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.1you are the absolute best.
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