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tatumnolan

  • one year ago

Would anyone want to help me on my 10 question worksheet on Statistical Analysis? It shouldn't be to hard for you and it would really help me

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  1. ganeshie8
    • one year ago
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    please post the question, somebody will help im sure

  2. tatumnolan
    • one year ago
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    https://gyazo.com/008d0397fa0457b385f6ae4c17a56059

  3. tatumnolan
    • one year ago
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    thats question 2

  4. ganeshie8
    • one year ago
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    look at the given dot plot do you see any outlier ?

  5. tatumnolan
    • one year ago
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    Yes

  6. tatumnolan
    • one year ago
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    The dot on 10

  7. ganeshie8
    • one year ago
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    Exactly, since an outlier is there, "median" is the best measure for center median is robust to outliers as the outliers don't affect median at all.

  8. tatumnolan
    • one year ago
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    ok so it would be median?

  9. ganeshie8
    • one year ago
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    Yes

  10. tatumnolan
    • one year ago
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    ok

  11. tatumnolan
    • one year ago
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    Ill post again if I need help on another question

  12. tatumnolan
    • one year ago
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    I Dont understand this subject its very odd for me

  13. tatumnolan
    • one year ago
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    https://gyazo.com/52e566d0b1ec8d591f1e2dcecf8f9eae

  14. tatumnolan
    • one year ago
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    Im sorry I feel like its c based on the last

  15. tatumnolan
    • one year ago
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    but im not sure

  16. ganeshie8
    • one year ago
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    do you see any outliers here ?

  17. tatumnolan
    • one year ago
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    Yes 2

  18. ganeshie8
    • one year ago
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    so use "inter quartile range" for spread

  19. tatumnolan
    • one year ago
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    Would it be Median again?

  20. tatumnolan
    • one year ago
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    oh

  21. ganeshie8
    • one year ago
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    "median", "mean" measure "center "mean absolute deviation". "interquartile range" measure variability

  22. tatumnolan
    • one year ago
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    Ugh Im so confused

  23. ganeshie8
    • one year ago
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    when you have outliers, use below : 1) median for center 2) interquartile range for variability

  24. tatumnolan
    • one year ago
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    ok

  25. tatumnolan
    • one year ago
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    THanks

  26. tatumnolan
    • one year ago
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    mean absolute deviation right?

  27. ganeshie8
    • one year ago
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    since you have outliers in the given bar chart, you would use "inter quartile range"

  28. tatumnolan
    • one year ago
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    I got confused and Put in interquartile range

  29. tatumnolan
    • one year ago
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    I got it wrong but right the second time

  30. tatumnolan
    • one year ago
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    sorry :/

  31. ganeshie8
    • one year ago
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    thats okay

  32. tatumnolan
    • one year ago
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    so can you give me a Definition for dummy's of mean absolute deviation

  33. tatumnolan
    • one year ago
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    ?

  34. ganeshie8
    • one year ago
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    mean absolute deviation as the name says, it sees how much far away each data value is located from the "mean"

  35. tatumnolan
    • one year ago
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    ok

  36. tatumnolan
    • one year ago
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    Thanks

  37. tatumnolan
    • one year ago
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    https://gyazo.com/e305909351cedb8e132801198f44f533 so for this one would I find the mean and then...

  38. tatumnolan
    • one year ago
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    or is there something else

  39. ganeshie8
    • one year ago
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    first find the mean

  40. tatumnolan
    • one year ago
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    ok

  41. tatumnolan
    • one year ago
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    is the mean 160?

  42. ganeshie8
    • one year ago
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    Correct

  43. tatumnolan
    • one year ago
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    Ok

  44. tatumnolan
    • one year ago
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    Next step?

  45. ganeshie8
    • one year ago
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    see how much far away each of the data point in given table from the mean

  46. ganeshie8
    • one year ago
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    simply subtract each of the given data point from the mean

  47. tatumnolan
    • one year ago
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    im confused

  48. tatumnolan
    • one year ago
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    what am I subtracting from 160?

  49. ganeshie8
    • one year ago
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    |dw:1440210090036:dw|

  50. tatumnolan
    • one year ago
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    39?

  51. ganeshie8
    • one year ago
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    Yes, find that for each row in the table

  52. tatumnolan
    • one year ago
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    oh boy

  53. tatumnolan
    • one year ago
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    ok

  54. tatumnolan
    • one year ago
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    and then what?

  55. ganeshie8
    • one year ago
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    |dw:1440210261023:dw|

  56. ganeshie8
    • one year ago
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    first do that, rest is easy il walk you through

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