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please post the question, somebody will help im sure
thats question 2
look at the given dot plot do you see any outlier ?
The dot on 10
Exactly, since an outlier is there, "median" is the best measure for center median is robust to outliers as the outliers don't affect median at all.
ok so it would be median?
Ill post again if I need help on another question
I Dont understand this subject its very odd for me
Im sorry I feel like its c based on the last
but im not sure
do you see any outliers here ?
so use "inter quartile range" for spread
Would it be Median again?
"median", "mean" measure "center "mean absolute deviation". "interquartile range" measure variability
Ugh Im so confused
when you have outliers, use below : 1) median for center 2) interquartile range for variability
mean absolute deviation right?
since you have outliers in the given bar chart, you would use "inter quartile range"
I got confused and Put in interquartile range
I got it wrong but right the second time
so can you give me a Definition for dummy's of mean absolute deviation
mean absolute deviation as the name says, it sees how much far away each data value is located from the "mean"
https://gyazo.com/e305909351cedb8e132801198f44f533 so for this one would I find the mean and then...
or is there something else
first find the mean
is the mean 160?
see how much far away each of the data point in given table from the mean
simply subtract each of the given data point from the mean
what am I subtracting from 160?
Yes, find that for each row in the table
and then what?
first do that, rest is easy il walk you through