anonymous
  • anonymous
Please I really need help Can someone help me if I type it all out? Posts longer than 2 sentences on here seem to scare people on here, but I will fan and medal.
Mathematics
katieb
  • katieb
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arindameducationusc
  • arindameducationusc
which data?
arindameducationusc
  • arindameducationusc
regression, never tried. But I am good with equations and straight lines I will try
anonymous
  • anonymous
I am going to type it, I seem to keep scaring people off with my table and work.

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anonymous
  • anonymous
I'm just going to lay it all out okay?
arindameducationusc
  • arindameducationusc
haha
anonymous
  • anonymous
that's all my work
arindameducationusc
  • arindameducationusc
okay.... I will try okay.. I cant guarantee, but I will do my best
anonymous
  • anonymous
thank you so much it means so much to me. I am so stressed about this
arindameducationusc
  • arindameducationusc
Are you taking x as 'avrge weekly paycheck'?
anonymous
  • anonymous
yes
anonymous
  • anonymous
@peachpi can you help at all?
arindameducationusc
  • arindameducationusc
Rate of change are absolutely correct, ya but the graph...!! hmmm... let me think.....
anonymous
  • anonymous
the line regression has to be least squares or line of best-fit
arindameducationusc
  • arindameducationusc
@lostinrome Is your cell phone android... I can give you a name of a software which deals with regressions
anonymous
  • anonymous
I'm on my laptop right now
anonymous
  • anonymous
^ I was just going to ask if this has to be done by hand. Excel does linear regression
anonymous
  • anonymous
yeah I have to come up with an equation (this whole thing is all on paper)
arindameducationusc
  • arindameducationusc
I graphed it in my mobile, should I send you the screen shot?
anonymous
  • anonymous
I'm not sure where to even start the linear regression and how I get an equation from it
arindameducationusc
  • arindameducationusc
equation I am getting -1.951402x+1040.6445224
anonymous
  • anonymous
I haven't done this in years. I'm looking some equations up
anonymous
  • anonymous
I don't have excel on my laptop so I can't use that
arindameducationusc
  • arindameducationusc
@phi is a very helpful person. He will help once he is online, just keep the question open
anonymous
  • anonymous
this is bad I really don't know what to do and I'm like freaking out
anonymous
  • anonymous
when does @phi come on usually?
arindameducationusc
  • arindameducationusc
Don't know actually, but he will help. He has helped me a lot in my complicated problems!
anonymous
  • anonymous
Fill in the table. In the third column, square the x values. In the fourth, multiply x and y. Add up the numbers in each column for the box at the bottom |dw:1440211191451:dw|
anonymous
  • anonymous
okay let me see
anonymous
  • anonymous
yes
anonymous
  • anonymous
Once we have the table filled in these are the formulas we're going to use to write the line in y = ax + b format |dw:1440211851554:dw|
anonymous
  • anonymous
i'm still typing in the table so give me a sec
anonymous
  • anonymous
|dw:1440211921215:dw|
anonymous
  • anonymous
okay now to write the line in y = ax + b format
anonymous
  • anonymous
so how do we apply the table to those formulas
anonymous
  • anonymous
I've seen those formulas before, but have a hard time understanding them.
anonymous
  • anonymous
ok so now we're going to use the sums at the bottom of the table. To put each sum in the right place, you just need to pay attention to the x's and y's and their exponents n is the number of points, so \(n = 6\) \[\sum_{i=1}^{6}x_i=96\] \[\sum_{i=1}^{6}y_i=5695\] \[\sum_{i=1}^{6}x^2_i=1606\] \[\sum_{i=1}^{6}x_iy_i=99055\] Putting all that into the equation for a we get \[a=\frac{ 6(99055)-(96)(5695) }{ 6(1606)-(96)^2 }\]
anonymous
  • anonymous
okay that makes sense
anonymous
  • anonymous
a = 1587/14 ?
anonymous
  • anonymous
yes :)
anonymous
  • anonymous
now for b \[b=\frac{ 1 }{ 6 }\left( 5695-\frac{ 1587 }{ 14 }(96) \right)\]
anonymous
  • anonymous
At this point you might find it easier to change these to decimals and round to 2 or 3 decimal places
anonymous
  • anonymous
I'm having trouble finding the decimal for b
anonymous
  • anonymous
b=(1/6)(5695-10882.29) =(1/6)(5187.29) = -864.55
anonymous
  • anonymous
yeah
anonymous
  • anonymous
y = 113.35x + -864.55
anonymous
  • anonymous
what do i do for the x in there?
anonymous
  • anonymous
the x stays. It's part of the equation
anonymous
  • anonymous
okay thought so. Wait was this whole thing in least squares or line of best-fit?
anonymous
  • anonymous
least squares
anonymous
  • anonymous
from excel |dw:1440214055244:dw|
anonymous
  • anonymous
okay and now for my millionth question, I have to get the slope of this equation we came up with and compare to the rate of change values I did.
anonymous
  • anonymous
I'm going to try and find the slope.
anonymous
  • anonymous
The slope is the "a" we found 113.36
anonymous
  • anonymous
oh slope of y = 113.35x + -864.55 is 113.36? Okay
anonymous
  • anonymous
oh, ok. it should have been rounded up to 113.36
anonymous
  • anonymous
so slope is 113.36
anonymous
  • anonymous
Yes. And for the rates of change you found above, you ended up with the right results, but the equations are backwards. For example the first one should be m= (810 - 585)/(15-13) m = 225/2 m = 112.5
anonymous
  • anonymous
Oh one more thing if you don't mind or if @arindameducationusc can pitch in if @peachpi is tired of me lol
arindameducationusc
  • arindameducationusc
hehe :D
anonymous
  • anonymous
It looks like the x's were years of schooling, so plug in 23 for x in the equation you found and solve for y
anonymous
  • anonymous
right
anonymous
  • anonymous
You are awesome. Thank you again!
anonymous
  • anonymous
I want to give you like 50 medals
anonymous
  • anonymous
lol you're welcome
anonymous
  • anonymous
yeah that's the right formula. Maybe you just typed them in reverse up top, because you ended up with the right numbers at the end
anonymous
  • anonymous
Yeah looking back I think that's what happened.
anonymous
  • anonymous
ok cool
anonymous
  • anonymous
:)

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