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anonymous
 one year ago
What is lim (cos((pi/2)+h)  cos(pi/2))/h?
h>0
anonymous
 one year ago
What is lim (cos((pi/2)+h)  cos(pi/2))/h? h>0

This Question is Closed

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Hint : Let \(f(x)=\cos(x)\) the given expression is equivalent to \(f'(\pi/2)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sin(h)0}{ h }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sin(h) }{ h }\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \color{red}{}\sin(h)0}{ h }\] right ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1because \(\cos(\pi/2 + x) =  \sin(x)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh ok! Is that like a identity?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1do you remember angle sum identity ? \(\cos(A+B)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sort of, it sounds familiar

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\cos(A+B) = \cos A\cos B  \sin A\sin B\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1use that to work out \(\cos(\pi/2+h)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhhhh that makes so much sense now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sin(h) }{ h }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So do I substitute 0 for h now?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1substitute h=0 and see what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh yea that doesn't work with 0 on the bottom oops!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1right, try using the standard limits dw:1440215549795:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes : \[\large \lim\limits_{h\to 0}~\dfrac{ \sin(h) }{ h } = \lim\limits_{h\to 0}~\dfrac{ \sin(h) }{ h } =1 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh I understand it all now!!! Thank you so much for teaching me you're great! :)
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