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Adi3
 one year ago
will medal
Please help
how to solve (x3)^2  (x+4)^2
Adi3
 one year ago
will medal Please help how to solve (x3)^2  (x+4)^2

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1wat do u want to solve?

Adi3
 one year ago
Best ResponseYou've already chosen the best response.17 (2x+1) this is the answer

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1we need to factor ths solution out to the answer igave u

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1but i dont know how to do tht

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, ok start of by expanding \[(x3)^2 = (x3)(x3)\] and do the same with the other expression

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You know how to distribute right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok go ahead and try :)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.2\(a^2b^2=(ab)(a+b)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x3)^2 \neq x^2+9\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.2\(a^2b^2=(ab)(a+b)\) Use that and we get \[(x3)^2(x4)^2=[(x3)+(x4)][(x3)(x4)]=(2x7)(1)\\=2x7\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1@iambatman isnt @zzr0ck3r doing the right thing

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.2Sorry to but in @iambatman I just thought this might be the best way to go about it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't worry about it! @Adi3 he's doing it right, just another method!

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.2I suggest doing both @Adi3

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1the right answer is 7(2x + 1)

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1so how is @zzr0ck3r method correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There was a sign error it's (x+4)^2 but otherwise he's right!

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1i m sorry but i still dont get it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well lets do it both ways, so you can see, you can distribute and all that as I showed above or we can do it with zz's method \[a^2b^2=(ab)(a+b)\] here we let \[a^2 = (x3)^2\] and \[b^2=(x+4)^2\] setting up we have \[(x3)^2(x+4)^2=[(x3)+(x+4)][(x3)(x+4)]=7(2x+1)\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1i cant medal u both though i want to

Adi3
 one year ago
Best ResponseYou've already chosen the best response.1yep u r right everyone got a medal except @ganeshie8

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1@Adi3 you can medal both if you like both answers, there is a way to do it but it is not official yet
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