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Adi3

  • one year ago

will medal Please help how to solve (x-3)^2 - (x+4)^2

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  1. Adi3
    • one year ago
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    @ganeshie8

  2. Adi3
    • one year ago
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    @iambatman

  3. ganeshie8
    • one year ago
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    wat do u want to solve?

  4. Adi3
    • one year ago
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    (x-3)^2 - (x+4)^2

  5. anonymous
    • one year ago
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    solve for x or what

  6. Adi3
    • one year ago
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    -7 (2x+1) this is the answer

  7. Adi3
    • one year ago
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    we need to factor ths solution out to the answer igave u

  8. Adi3
    • one year ago
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    but i dont know how to do tht

  9. anonymous
    • one year ago
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    Ah, ok start of by expanding \[(x-3)^2 = (x-3)(x-3)\] and do the same with the other expression

  10. anonymous
    • one year ago
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    You know how to distribute right?

  11. Adi3
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    Ok go ahead and try :)

  13. zzr0ck3r
    • one year ago
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    \(a^2-b^2=(a-b)(a+b)\)

  14. Adi3
    • one year ago
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    x^2 + 9

  15. Adi3
    • one year ago
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    @zzr0ck3r wht next

  16. anonymous
    • one year ago
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    \[(x-3)^2 \neq x^2+9\]

  17. zzr0ck3r
    • one year ago
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    \(a^2-b^2=(a-b)(a+b)\) Use that and we get \[(x-3)^2-(x-4)^2=[(x-3)+(x-4)][(x-3)-(x-4)]=(2x-7)(1)\\=2x-7\]

  18. Adi3
    • one year ago
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    @iambatman isnt @zzr0ck3r doing the right thing

  19. zzr0ck3r
    • one year ago
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    Sorry to but in @iambatman I just thought this might be the best way to go about it.

  20. anonymous
    • one year ago
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    Don't worry about it! @Adi3 he's doing it right, just another method!

  21. zzr0ck3r
    • one year ago
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    I suggest doing both @Adi3

  22. Adi3
    • one year ago
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    the right answer is -7(2x + 1)

  23. Adi3
    • one year ago
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    so how is @zzr0ck3r method correct

  24. anonymous
    • one year ago
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    There was a sign error it's (x+4)^2 but otherwise he's right!

  25. Adi3
    • one year ago
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    i m sorry but i still dont get it

  26. anonymous
    • one year ago
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    Well lets do it both ways, so you can see, you can distribute and all that as I showed above or we can do it with zz's method \[a^2-b^2=(a-b)(a+b)\] here we let \[a^2 = (x-3)^2\] and \[b^2=(x+4)^2\] setting up we have \[(x-3)^2-(x+4)^2=[(x-3)+(x+4)][(x-3)-(x+4)]=-7(2x+1)\]

  27. Adi3
    • one year ago
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    ohh now i get it

  28. Adi3
    • one year ago
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    thnxs who should i medal

  29. Adi3
    • one year ago
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    i cant medal u both though i want to

  30. Adi3
    • one year ago
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    so who should i medal

  31. anonymous
    • one year ago
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    Ganeshie!

  32. Adi3
    • one year ago
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    yep u r right everyone got a medal except @ganeshie8

  33. anonymous
    • one year ago
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    Hehe

  34. ganeshie8
    • one year ago
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    @Adi3 you can medal both if you like both answers, there is a way to do it but it is not official yet

  35. Adi3
    • one year ago
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    nice

  36. Adi3
    • one year ago
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    alright thnxs everyone

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