anonymous
  • anonymous
Example 4 on http://tutorial.math.lamar.edu/Classes/CalcIII/DIPolarCoords.aspx Why is this correct? How does subtracting the volume under z = 16 from the volume under z = x^2 + y^2 on a specific radius give us the desired volume?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Sorry dude the link doesn't work....
anonymous
  • anonymous
Is this Calc 3?
anonymous
  • anonymous
Sorry, I fixed it now. Yes it is.

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anonymous
  • anonymous
Wow... I am sorry I can't help. I just started Calculus - I am only in tenth grade. Sorry.
anonymous
  • anonymous
No problem :)
IrishBoy123
  • IrishBoy123
you're looking for the volume of the paraboloid itself, ie the volume inside that solid but the normal double integral of the function f, ie\( \iint f(x,y) \ dA \) will give you the volume under the pataboloid, ie the volume from the xy plane upwards
IrishBoy123
  • IrishBoy123
handily, though, that volume it does give you can be subtracted from the volume of the cylinder to get the inside volume. and by cylinder i mean the volume under the plane \(z = 16\) within the region \(16 = x^2 + y^2\)
phi
  • phi
In 2D they are doing this |dw:1440248565912:dw| that is the integral under the curve f(x)
phi
  • phi
but if we want the area (or in 3D, the volume) of the "inside" |dw:1440248674950:dw|
phi
  • phi
then we find the area of the enclosing rectangle (cylinder in 3D) and subtract off the area of f(x) |dw:1440248748282:dw|

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