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anonymous
 one year ago
Hi can someone help me with this table and graph stuff for algebra?
anonymous
 one year ago
Hi can someone help me with this table and graph stuff for algebra?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess it could be either linear or cubic. It kind of looks like there's an inflection point between 1974 and 1975. Do you have to find the equation by hand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it doesn't really say, but it would probably be for the best.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok well if you have to do it by hand, it's probably linear. least square regression?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It doesn't say specifically but that should work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have to change your table to do this. The ycolumn is fine the way it is. The xcolumn needs to start at 0. So let 1885 be year 0 and let x be years after 1885. So like 1917 will be 32, 1919 will be 34, etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay wait I think I misinterpreted what you typed. I have to change the table to find an equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, we're looking for an equation in y = mx + b form. If you leave the table like that it will skew the yintercept ( I believe)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right okay I think I follow you a little.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is making the gears in my head spin lol I know the equation has to be y=mx + b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is one I helped someone with last night. Scroll to about the middle of the page. Do the formulas for a and b look familiar? http://openstudy.com/users/peachpi#/updates/55d7dbd9e4b02663346b9fa8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yeah! I've seen those before. I mean I always get the numbers mixed up. I wouldn't know where to put what.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's fine. Just start with adjusting the years and we'll go from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I feel like that table on that page or whatever has specific numbers for the x's and y's. I wouldn't know which ones to apply for my situation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your y's are going to be the stamp's costs (0.02, 0.03, 0.02, 0.03, etc.) Your x's are going to be years since 1885 (0, 32, 34, 47, etc). Subtract 1885 from each year to get these

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh that's how you got those, ok.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you have excel, google docs, or some other spreadsheet program it will do the calculations for you and you just have to arrange the table

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I had excel but the trial ended. I don't really have any way to do this. I don't know I gotta think about this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for that girl you did a table that was xyx^2xy is that what I have to do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh man okay x would start with 0? I think you said. I'm sorry I'm so hopeless I'm getting myself confused all over again.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or would the x and y columns look exactly like my table? and then I would multiply x by itself and then I multiply x and y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold up. I don't think those are going to be the right equations anyway. I think this might be exponential. It just doesn't look so on your graph because the years aren't evenly spaced. This is what I get with an evenly spaces xaxis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440245393715:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I did my graph wrong? Or that's a new graph over my original graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, your graph is wrong. You used 1 square for each difference in years, but the differences aren't all the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so do I need to redo the years on my graph? I actually wasnt sure how to space them. I only had like 25 spaces. Yeah the years aren't spaced correctly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what spacing would you recommend I use?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can use the spacing you used for the y axis, but I'm not sure for the x axis.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so we're going from 1885 to 2012, that's 127 years. Divide by 25 to get 5.02, so make every space 6 years to have a little extra room on the right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't put the actual years on the graph. so start at 0, then 6, 12, 18 etc. Then use a label that says "Years since 1885"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry for being so confused. I'm really trying to understand this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i didn't label the years but started with 0 and ended with 138 (that's as far as my graph will let me go)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00 represents 1885. 6 represents 1891. 12 represents 1897. Even though 1891 won't be a point on the graph, we have to show it on the xaxis to show how long it's taking the price to rise at the beginning. 1917 is 32 years after 1885. So that point will be about 5 or 6 grid lines right of the first point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I'm gonna need a much bigger graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No your graph is fine. 2012 is 127 years after 1885. Your graph is showing 138 years after, so we have a little extra. That's exactly what we want

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you done the thing where you subtract 1885 from all the years yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the y axis okay? I went by 2's on there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes the yaxis is good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wasn't sure what you meant by that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like this 1885  1885 = 0 19171885 = 32 1919  1885 = 34

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay well I'll do all those and get back to you okay?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. At the bottom of the page are the equations for curve fitting an exponential function (lowercase a and b). http://mathworld.wolfram.com/LeastSquaresFittingExponential.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then I need to square the x's and then multiply x and y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this one isn't linear so the equations are different. Have you seen those before? I had a hard time even finding them, so I'm wondering if you're supposed to do this using technology as opposed to hand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No I haven't really seen them before (hence my yikes lol) This is on a worksheet so I just assumed it was by hand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I feel like my heads gonna explode.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you have or want to create a google account, google docs will calculate the curve once you enter the data in their spreadsheet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just have a really hard time thinking they want an algebra student to do this by hand :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've never used spreadsheets before. How do I see the curve in the spreadsheet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have to enter the table and then create the chart. I can walk you through it. Search for google docs then sign in to create a spreadsheet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I'm on the spreadsheet (that link you gave me that you did last night since her graph thing was linear and my is expo than how I find an equation is different?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Linear is y = mx + b Exponential is \(y=ab^x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay gotcha well i'm on the spread sheet now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you explain to me why it is expo? I don't think we went over that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. so now make columns for x and y. Put the x column to the left and enter the numbers you got by subtracting (0, 32, etc) and another for the prices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0make the correct graph first. It will be easier to understand that way. You really wouldn't know whether it was linear or exponential once you see the graph.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*until you see the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in the A column put 0 32 34 47 all the way ↓ to 127 In the B column 0.02 0.03 0.02 0.03 ↓ 0.45

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay let me do all of that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I labeled the two sides of the table (years were x) (y were costs)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay now what do I do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. now highlight the cells with numbers in them and go to the INSERT menu at the top and select CHART

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0stupid question  how do I highlight them w/o highlight the little grey column on the left?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's going to highlight automatically so you know which cells are selected. It's fine. Once you pick Chart A box should pop up with named Chart Editor with Recommendations, Chart Types, and Customization tabs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't think it matters

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I did insert and selected chart

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm in the chart editor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One of the recommended charts should a grid showing dot. Select that one and hit INSERT at the bottom

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to screencap and upload it to make sure it looks good?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure if that looks right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hm seems like I missed something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the most part it looks right. Maybe one of us made a typo when entering the points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah could be. I really don't think they will notice too much. it's fine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll leave it to you to check, but we can go on so you know how to get the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you notice how it almost flat toward the left and then increases steeply toward the right? That's how I know it's exponential

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440249587962:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The graph on the right is linear functions. They have the same slope everywher

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To get the equation of your graph hit the little triangle on the top right corner of the graph and select ADVANCED EDIT

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then go down to where it has TRENDLINE and select EXPONENTIAL For LABEL select USE EQUATION

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you see the equation to the right of the graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do I see all of it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can make the chart bigger. grab one of the handles on the corner to stretch it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that's my equation then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah mine is 8.66 instead of 9.538 yeah that's the equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you tell me your full equation just incase mine was the one that wasn't 100% correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mine was (8.661E3)e^(0.03x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You should probably write it in decimal form though. So yours would be 0.009538e^(0.03x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(move the decimal point left 3 times and drop the E)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0math teachers don't generally like E format

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0don't put it in y=ab^x form?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is. a = 0.009538 b = e^0.03

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay I see didn't know if y= is relevant or not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It should be y = 0.009538e^(0.03x) as your final equation. (the  I put there was a mistake)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how can I use that equation to predict from 20132022 Do I change something in it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or bring the costs back in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For 2013  2022, you have to plug the xvalues into the equation to get predictions. For example: 2013  1885 = 128 So plug in 128 into your equation y = 0.009538e^(0.03*128) y = 0.44376 y = $0.44

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0awesome! Okay I just want to thank you so much for everything. Like you are a life saver. <333 The best
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