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anonymous

  • one year ago

Hi can someone help me with this table and graph stuff for algebra?

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  1. anonymous
    • one year ago
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    I guess it could be either linear or cubic. It kind of looks like there's an inflection point between 1974 and 1975. Do you have to find the equation by hand?

  2. anonymous
    • one year ago
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    it doesn't really say, but it would probably be for the best.

  3. anonymous
    • one year ago
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    ok well if you have to do it by hand, it's probably linear. least square regression?

  4. anonymous
    • one year ago
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    It doesn't say specifically but that should work.

  5. anonymous
    • one year ago
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    you have to change your table to do this. The y-column is fine the way it is. The x-column needs to start at 0. So let 1885 be year 0 and let x be years after 1885. So like 1917 will be 32, 1919 will be 34, etc

  6. anonymous
    • one year ago
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    okay wait I think I misinterpreted what you typed. I have to change the table to find an equation?

  7. anonymous
    • one year ago
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    Yeah, we're looking for an equation in y = mx + b form. If you leave the table like that it will skew the y-intercept ( I believe)

  8. anonymous
    • one year ago
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    right okay I think I follow you a little.

  9. anonymous
    • one year ago
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    this is making the gears in my head spin lol I know the equation has to be y=mx + b

  10. anonymous
    • one year ago
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    This is one I helped someone with last night. Scroll to about the middle of the page. Do the formulas for a and b look familiar? http://openstudy.com/users/peachpi#/updates/55d7dbd9e4b02663346b9fa8

  11. anonymous
    • one year ago
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    oh yeah! I've seen those before. I mean I always get the numbers mixed up. I wouldn't know where to put what.

  12. anonymous
    • one year ago
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    that's fine. Just start with adjusting the years and we'll go from there

  13. anonymous
    • one year ago
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    I feel like that table on that page or whatever has specific numbers for the x's and y's. I wouldn't know which ones to apply for my situation.

  14. anonymous
    • one year ago
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    Your y's are going to be the stamp's costs (0.02, 0.03, 0.02, 0.03, etc.) Your x's are going to be years since 1885 (0, 32, 34, 47, etc). Subtract 1885 from each year to get these

  15. anonymous
    • one year ago
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    oh that's how you got those, ok.

  16. anonymous
    • one year ago
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    If you have excel, google docs, or some other spreadsheet program it will do the calculations for you and you just have to arrange the table

  17. anonymous
    • one year ago
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    I had excel but the trial ended. I don't really have any way to do this. I don't know I gotta think about this.

  18. anonymous
    • one year ago
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    for that girl you did a table that was x|y|x^2|xy is that what I have to do?

  19. anonymous
    • one year ago
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    yeah

  20. anonymous
    • one year ago
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    oh man okay x would start with 0? I think you said. I'm sorry I'm so hopeless I'm getting myself confused all over again.

  21. anonymous
    • one year ago
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    or would the x and y columns look exactly like my table? and then I would multiply x by itself and then I multiply x and y?

  22. anonymous
    • one year ago
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    hold up. I don't think those are going to be the right equations anyway. I think this might be exponential. It just doesn't look so on your graph because the years aren't evenly spaced. This is what I get with an evenly spaces x-axis

  23. anonymous
    • one year ago
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    |dw:1440245393715:dw|

  24. anonymous
    • one year ago
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    so I did my graph wrong? Or that's a new graph over my original graph?

  25. anonymous
    • one year ago
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    no, your graph is wrong. You used 1 square for each difference in years, but the differences aren't all the same

  26. anonymous
    • one year ago
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    so do I need to redo the years on my graph? I actually wasnt sure how to space them. I only had like 25 spaces. Yeah the years aren't spaced correctly.

  27. anonymous
    • one year ago
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    what spacing would you recommend I use?

  28. anonymous
    • one year ago
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    I can use the spacing you used for the y axis, but I'm not sure for the x axis.

  29. anonymous
    • one year ago
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    Ok so we're going from 1885 to 2012, that's 127 years. Divide by 25 to get 5.02, so make every space 6 years to have a little extra room on the right

  30. anonymous
    • one year ago
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    Don't put the actual years on the graph. so start at 0, then 6, 12, 18 etc. Then use a label that says "Years since 1885"

  31. anonymous
    • one year ago
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    I'm sorry for being so confused. I'm really trying to understand this

  32. anonymous
    • one year ago
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    so i didn't label the years but started with 0 and ended with 138 (that's as far as my graph will let me go)

  33. anonymous
    • one year ago
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    0 represents 1885. 6 represents 1891. 12 represents 1897. Even though 1891 won't be a point on the graph, we have to show it on the x-axis to show how long it's taking the price to rise at the beginning. 1917 is 32 years after 1885. So that point will be about 5 or 6 grid lines right of the first point

  34. anonymous
    • one year ago
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    okay I'm gonna need a much bigger graph

  35. anonymous
    • one year ago
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    No your graph is fine. 2012 is 127 years after 1885. Your graph is showing 138 years after, so we have a little extra. That's exactly what we want

  36. anonymous
    • one year ago
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    okay

  37. anonymous
    • one year ago
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    Have you done the thing where you subtract 1885 from all the years yet?

  38. anonymous
    • one year ago
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    is the y axis okay? I went by 2's on there?

  39. anonymous
    • one year ago
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    yes the y-axis is good

  40. anonymous
    • one year ago
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    I wasn't sure what you meant by that.

  41. anonymous
    • one year ago
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    like this 1885 - 1885 = 0 1917-1885 = 32 1919 - 1885 = 34

  42. anonymous
    • one year ago
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    oh okay well I'll do all those and get back to you okay?

  43. anonymous
    • one year ago
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    ok.

  44. anonymous
    • one year ago
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    almost done...

  45. anonymous
    • one year ago
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    ok

  46. anonymous
    • one year ago
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    ok. At the bottom of the page are the equations for curve fitting an exponential function (lowercase a and b). http://mathworld.wolfram.com/LeastSquaresFittingExponential.html

  47. anonymous
    • one year ago
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    then I need to square the x's and then multiply x and y

  48. anonymous
    • one year ago
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    oh man yikes okay

  49. anonymous
    • one year ago
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    this one isn't linear so the equations are different. Have you seen those before? I had a hard time even finding them, so I'm wondering if you're supposed to do this using technology as opposed to hand

  50. anonymous
    • one year ago
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    No I haven't really seen them before (hence my yikes lol) This is on a worksheet so I just assumed it was by hand

  51. anonymous
    • one year ago
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    I feel like my heads gonna explode.

  52. anonymous
    • one year ago
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    If you have or want to create a google account, google docs will calculate the curve once you enter the data in their spreadsheet

  53. anonymous
    • one year ago
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    I just have a really hard time thinking they want an algebra student to do this by hand :/

  54. anonymous
    • one year ago
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    I've never used spreadsheets before. How do I see the curve in the spreadsheet?

  55. anonymous
    • one year ago
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    you have to enter the table and then create the chart. I can walk you through it. Search for google docs then sign in to create a spreadsheet

  56. anonymous
    • one year ago
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    okay I'm on the spreadsheet (that link you gave me that you did last night since her graph thing was linear and my is expo than how I find an equation is different?

  57. anonymous
    • one year ago
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    Linear is y = mx + b Exponential is \(y=ab^x\)

  58. anonymous
    • one year ago
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    okay gotcha well i'm on the spread sheet now

  59. anonymous
    • one year ago
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    can you explain to me why it is expo? I don't think we went over that

  60. anonymous
    • one year ago
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    ok. so now make columns for x and y. Put the x column to the left and enter the numbers you got by subtracting (0, 32, etc) and another for the prices

  61. anonymous
    • one year ago
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    make the correct graph first. It will be easier to understand that way. You really wouldn't know whether it was linear or exponential once you see the graph.

  62. anonymous
    • one year ago
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    *until you see the graph

  63. anonymous
    • one year ago
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    so in the A column put 0 32 34 47 all the way ↓ to 127 In the B column 0.02 0.03 0.02 0.03 ↓ 0.45

  64. anonymous
    • one year ago
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    okay let me do all of that

  65. anonymous
    • one year ago
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    I labeled the two sides of the table (years were x) (y were costs)

  66. anonymous
    • one year ago
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    okay now what do I do?

  67. anonymous
    • one year ago
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    ok. now highlight the cells with numbers in them and go to the INSERT menu at the top and select CHART

  68. anonymous
    • one year ago
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    stupid question - how do I highlight them w/o highlight the little grey column on the left?

  69. anonymous
    • one year ago
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    That's going to highlight automatically so you know which cells are selected. It's fine. Once you pick Chart A box should pop up with named Chart Editor with Recommendations, Chart Types, and Customization tabs

  70. anonymous
    • one year ago
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    I don't think it matters

  71. anonymous
    • one year ago
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    ok

  72. anonymous
    • one year ago
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    okay I did insert and selected chart

  73. anonymous
    • one year ago
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    i'm in the chart editor

  74. anonymous
    • one year ago
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    One of the recommended charts should a grid showing dot. Select that one and hit INSERT at the bottom

  75. anonymous
    • one year ago
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    okay

  76. anonymous
    • one year ago
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    done

  77. anonymous
    • one year ago
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    do you want me to screencap and upload it to make sure it looks good?

  78. anonymous
    • one year ago
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    yes please

  79. anonymous
    • one year ago
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    not sure if that looks right

  80. anonymous
    • one year ago
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    This is mine

    1 Attachment
  81. anonymous
    • one year ago
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    hm seems like I missed something

  82. anonymous
    • one year ago
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    For the most part it looks right. Maybe one of us made a typo when entering the points

  83. anonymous
    • one year ago
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    yeah could be. I really don't think they will notice too much. it's fine

  84. anonymous
    • one year ago
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    I'll leave it to you to check, but we can go on so you know how to get the equation

  85. anonymous
    • one year ago
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    okay

  86. anonymous
    • one year ago
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    Do you notice how it almost flat toward the left and then increases steeply toward the right? That's how I know it's exponential

  87. anonymous
    • one year ago
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    right

  88. anonymous
    • one year ago
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    |dw:1440249587962:dw|

  89. anonymous
    • one year ago
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    The graph on the right is linear functions. They have the same slope everywher

  90. anonymous
    • one year ago
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    I see

  91. anonymous
    • one year ago
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    To get the equation of your graph hit the little triangle on the top right corner of the graph and select ADVANCED EDIT

  92. anonymous
    • one year ago
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    okay

  93. anonymous
    • one year ago
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    Then go down to where it has TRENDLINE and select EXPONENTIAL For LABEL select USE EQUATION

  94. anonymous
    • one year ago
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    okay

  95. anonymous
    • one year ago
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    then input?

  96. anonymous
    • one year ago
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    or update I guess

  97. anonymous
    • one year ago
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    oh yeah hit update

  98. anonymous
    • one year ago
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    ok

  99. anonymous
    • one year ago
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    do you see the equation to the right of the graph?

  100. anonymous
    • one year ago
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    how do I see all of it?

  101. anonymous
    • one year ago
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    you can make the chart bigger. grab one of the handles on the corner to stretch it

  102. anonymous
    • one year ago
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    so that's my equation then

  103. anonymous
    • one year ago
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    yeah mine is 8.66 instead of 9.538 yeah that's the equation.

  104. anonymous
    • one year ago
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    can you tell me your full equation just incase mine was the one that wasn't 100% correct?

  105. anonymous
    • one year ago
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    Mine was (8.661E-3)e^(0.03x)

  106. anonymous
    • one year ago
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    awesome thank you

  107. anonymous
    • one year ago
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    You should probably write it in decimal form though. So yours would be 0.009538e^(-0.03x)

  108. anonymous
    • one year ago
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    (move the decimal point left 3 times and drop the E)

  109. anonymous
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    math teachers don't generally like E format

  110. anonymous
    • one year ago
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    don't put it in y=ab^x form?

  111. anonymous
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    It is. a = 0.009538 b = e^0.03

  112. anonymous
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    oh okay I see didn't know if y= is relevant or not.

  113. anonymous
    • one year ago
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    It should be y = 0.009538e^(0.03x) as your final equation. (the - I put there was a mistake)

  114. anonymous
    • one year ago
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    okay

  115. anonymous
    • one year ago
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    so how can I use that equation to predict from 2013-2022 Do I change something in it?

  116. anonymous
    • one year ago
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    or bring the costs back in?

  117. anonymous
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    For 2013 - 2022, you have to plug the x-values into the equation to get predictions. For example: 2013 - 1885 = 128 So plug in 128 into your equation y = 0.009538e^(0.03*128) y = 0.44376 y = $0.44

  118. anonymous
    • one year ago
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    $0.46

  119. anonymous
    • one year ago
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    yeah $0.46

  120. anonymous
    • one year ago
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    awesome! Okay I just want to thank you so much for everything. Like you are a life saver. <333 The best

  121. anonymous
    • one year ago
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    You're welcome :)

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