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the area of a square is 5 more than its perimeter. find the length of a side.
my work so far: 4r=r^2+5 r^2-4r+5=0 then I am supposed to factor? I cannot figure out how to factor this! I literally tried every possible way.. :( someone please help me?
Good morning I think I mIght be able to assist
I bRelieve your doing it correctly so far
Hey that's what I'm here for
Ok I'm back Olivia
And thX for the compliment I appreciate it
ok im here! :)
Are we reading it correctly? Area = Perimeter + 5 how do we define area and perimeter of a square ?
yes I believe so.. And im not sure, I honestly just follow the practice problems along with the actual problem to solve it. :/
area, is 5 more than perimeter area = perimeter + 5 area = r^2, and perimeter is 4r youre initial setup seems flawed to me
ok, like i said I was just following the practice problem so the way I set it up is probably wrong. how would you set it up?
the way i have already set it up ... area = perimeter + 5
ok but how would i solve that? thanks for ur help btw!
the area of a square is 5 more than its perimeter ^^^ = ^ ^^^ ^^^^^^^ r^2 = 4r + 5 area = perimeter + 5 ------------------ but you setup as: 4r = r^2 + 5 perimeter = area + 5 ------------------- solving it is just finding the solutions to the quadratic, factor if you can (it most likely factorable)
r^2 -4r -5 = 0
ok give me a second to factor it
any thoughts about how we could factor it?
you did fine with the factoring
ok, so it would solve to be r=-1, and r=5...so it would be 5 units?
5 is the workable length, -1 is just a extra value that doesnt fit with the expected domain and can be ignored 5 is fine
yay is what right! thanks so much for your help it was a lot easier than i thought :p
ive had years of practice :) youll do fine