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anonymous
 one year ago
The graph of a function f is given above.
anonymous
 one year ago
The graph of a function f is given above.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is \[\lim_{x \rightarrow 2}\frac{ x }{ f(x)+1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440258551985:dw

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0well, start by finding f(2)

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0its infinity this lim but dont know + or 

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I know if it's positive or negative Infiniti?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.21  (something smaller than 1) is a positive number; and x=2 is a positive number +/+ = +

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440260968991:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I forgot to make the bottom of the graph negative oops :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440261046439:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you see that for say x between 1 and 3, that the top of the setup is positive and that the bottome part: f(1,3) + 1 is just the same as: 1  (a fraction) is positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get f(1,3) +1 and 1(a fraction)?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i glossed over x=2 :) other than that you see that f(x) is a value between 0 and 1 right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2and saying "a fraction" is lazy as well, since the values are both rational and irrational.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok :) so f(1,3) means those are the x values that cross on 0 and that's why you add 1?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2f(x) + 1 is the bottom of your setup and if we just focus on the values between 1 and 3; f(1,3) just denotes all the values we can conceive of yes

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2x = (1,3) includes x=2 f(1,3) includes all the values that x produces along the stated domain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So do I solve for 1 first, and the 3?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2no, i was just making an observation the value of the bottom, when x=2, is 0 since f(2) = 1 now, the limit is defined if the value that is approached from the left and right of x=2 is the same. so we observe that for a small enough region around x=2, the top is always positive, and the bottom is always positive; therefore, we approach the same infinity (+inf). but in may classes, infinity is still classified as DNE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh ok I understand now :)
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