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let W = width L = length perimeter = 2(L+W) L = W + 4 do you think you can take it from here?
no i dont understand any of this lol thats why im a senior retaking algebra one
well, to find the perimeter of a rectangle, we add the width and length, then multiply everything by 2, so perimeter = 2(L+W) make sense so far?
yes that makes sense
ok, the problem also tells us that "length is 4 more than the width" so L = W + 4, make sense so far?
great, now let's put them together and go from there perimeter = 50 = 2(L+W) L = W + 4 now, the second equation tells us that we can replace "L" with "W+4" whenever we see L, so we can plug that into the first equation, giving us: 50 = 2(L+W) = 2(W + 4 + W) with me so far?
well, the second equation tells us that "length" is the same as "width+4" so we can replace "length" with "width + 4". the reason why we do this is to make all the letters in the first equation the same, so we can find width 50 = 2(W + 4 + W) we can put W + W together to get 2W, which gives us 5= 2(2W+4), with me so far?
yes im with you
ok, so we have 50 = 2(2W+4) we can divide both sides by 2 to get 25 = (2W+4) do you think you can solve for W now?
i think i got it
ok, give it a shot and tell me what W is I'll guide you if you get stuck
ok i have no idea
no worries 25 = (2W+4) subtract 4 from each side, what do you get?
wait is the answer D
nope, not D, please try the problem with me 25 = (2W+4) subtract 4 from both sides of the equals sign
subtract 4 from 25 thats 21 ok
what about the right side? 2W + 4 - 4 = ?
its B :)