anonymous
  • anonymous
Can someone help me with this problem? I thought that you were just supposed to subtract "a-4" from the original problem to result in, 3a-12 but that is incorrect it says. Subtract "a-4" from "4a+16" and simplify your answer. The variable "a" should appear only once in your answer.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Problem with signs. Your idea is correct what happens when you subtract -4 from 16. \[16-\left( -4 \right) = ?\]
anonymous
  • anonymous
I guess
anonymous
  • anonymous
but how should I solve the problem

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anonymous
  • anonymous
All that I know is that 3a+12 is incorrect
anonymous
  • anonymous
\[\left( 4a+16 \right) - \left( a-4 \right) = 4a+16-a+4 = ?\]What do you get?
anonymous
  • anonymous
3a+20?
anonymous
  • anonymous
Correct. Good job. Do you understand where you went wrong the first time?
anonymous
  • anonymous
Yes I did not correctly follow the second step, the conversion between (a-4) and a+4 thankyou
anonymous
  • anonymous
You're welcome.

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