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anonymous

  • one year ago

Can someone help me with this problem? I thought that you were just supposed to subtract "a-4" from the original problem to result in, 3a-12 but that is incorrect it says. Subtract "a-4" from "4a+16" and simplify your answer. The variable "a" should appear only once in your answer.

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  1. anonymous
    • one year ago
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    Problem with signs. Your idea is correct what happens when you subtract -4 from 16. \[16-\left( -4 \right) = ?\]

  2. anonymous
    • one year ago
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    I guess

  3. anonymous
    • one year ago
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    but how should I solve the problem

  4. anonymous
    • one year ago
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    All that I know is that 3a+12 is incorrect

  5. anonymous
    • one year ago
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    \[\left( 4a+16 \right) - \left( a-4 \right) = 4a+16-a+4 = ?\]What do you get?

  6. anonymous
    • one year ago
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    3a+20?

  7. anonymous
    • one year ago
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    Correct. Good job. Do you understand where you went wrong the first time?

  8. anonymous
    • one year ago
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    Yes I did not correctly follow the second step, the conversion between (a-4) and a+4 thankyou

  9. anonymous
    • one year ago
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    You're welcome.

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spraguer (Moderator)
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